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3 years ago

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Carlotta subscribes to the HotBurn music service. She can download no more than 12 song files per week. Carlotta has already dow

nloaded 10 song files this week. Write, solve, and graph an inequality to show how many more songs Carlotta can download.

1 answer:

UNO [17]3 years ago

8 0

Answer:

Inequality: $x+10\leq 12$

Inequality solved: $x\leq 2$

The graph is attached.

Step-by-step explanation:

You need to remember the meaning of the inequalities symbols:

: Less than.

$>$ : Greater than.

$\leq$ : Less than or equal to.

$\geq$ : Greater than or equal to.

Let be "x" the number of more songs Carlotta can download.

According to the information given in the exercise, she can download no more than 12 song files per week. This indicates that you must use the symbol $\leq$ .

Since she has already downloaded 10 song files this week, you can write the following inequality that represents this situation:

$x+10\leq 12$

In order to solve it, you must subtract 10 from both sides:

$x+10-10\leq 12-10\\\\x\leq 2$

Plot this result on a number line.

Since the symbol of the inequality is $\leq$ , the dot must be filled (Observe the number line attached).

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Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

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