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NNADVOKAT [17]
3 years ago
6

A clerk counted 14 small baseball caps, 37 medium baseball caps, and 29 large baseball caps on the store shelves. She also count

ed 9 small baseball caps and 19 medium baseball caps in the stockroom.
(a.) Organize the data in a matrix. Name the matrix B. Label the rows and columns.
(b.) Each baseball cap sells for $16. Create the matrix that shows the total value of each cap size in each location.
Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

a.  

                                              S             M            L

B =           Shelves              14            37          29                

                 Stockroom          9            19            0

S - Small baseball caps

M- Medium baseball caps

L - Large baseball caps


b.

                           S              M            L  

Shelves             224          592       464              

Stockroom        144          304          0

S - Small baseball caps

M- Medium baseball caps

L - Large baseball caps

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A ​20-ft by ​the 40-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway i
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<h3>Answer:  2 feet</h3>

========================================================

Explanation:

x = width of the walkway in feet

This is some positive real number.

The dimension of 20 feet bumps up to 20+2x when adding on x from both directions. Similarly, the 40 ft dimension becomes 40+2x

Refer to the diagram below.

The 20 ft by 40 ft pool is surrounded by a larger rectangle that is 20+2x ft by 40+2x ft

The pool itself is 20*40 = 800 sq ft. Add on the walkway area to get 800+256 = 1056 sq ft.

-----------

Area = length*width

1056 = (20+2x)*(40+2x)

1056 = 20*40 + 20*2x + 2x*40 + 2x*2x ... FOIL rule

1056 = 800 + 40x + 80x + 4x^2

0 = 4x^2 + 40x + 80x + 800 - 1056

0 = 4x^2 + 120x - 256

4x^2 + 120x -  256 = 0

4(x^2 + 30x - 64) = 0

x^2 + 30x - 64 = 0

Let's use the quadratic formula to finish solving for x.

Plug in a = 1, b = 30, c = -64

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-30\pm\sqrt{(30)^2-4(1)(-64)}}{2(1)}\\\\x = \frac{-30\pm\sqrt{1156}}{2}\\\\x = \frac{-30\pm34}{2}\\\\x = \frac{-30+34}{2} \ \text{ or } \ x = \frac{-30-34}{2}\\\\x = \frac{4}{2} \ \text{ or } \ x = \frac{-64}{2}\\\\x = 2 \ \text{ or } \ x = -32\\\\

Recall we made x be positive. This is because a negative walkway width does not make sense. This means we'll ignore x = -32.

The only practical solution is x = 2

Therefore, the walkway is <u>2 feet wide</u>

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