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nikklg [1K]
3 years ago
6

If you draw three cards from a regular deck of 52 cards, keeping each card out of the deck after you draw it, what are the chanc

es you draw a seven and two queens?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0
There are four 7's in a standard card. Chance of getting a 7 first is 4/52 = 1/13
There are four queens in a standard card. Chance of getting a queen in the second drawing is 4/51 and chance of getting a queen in the third drawing is 3/50.

Therefore, chance of drawing a seven and two queens is 1/13 x 4/51 x 3/50 = 2/5525
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Citrus2011 [14]

Answer:

the answer is option B

Step-by-step explanation:

To find dy/dx the equation here is

first multipled by derivative of second + second multipled by derivative of first

y = x*sinx

dy/dx = x * derivative of sinx + sinx * derivative of x

derivative of x with respect to x is 1

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therefore

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3 years ago
The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (according to GolfWeek). Assume th
Usimov [2.4K]

Answer:

a) f(x) = \frac{1}{25.9}

b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b-a}

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.

This means that a = 284.7, b = 310.6.

a. Give a mathematical expression for the probability density function of driving distance.

f(x) = \frac{1}{b-a} = \frac{1}{310.6-284.7} = \frac{1}{25.9}

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

P(X < 290) = \frac{290 - 284.7}{310.6-284.7} = 0.2046

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

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2 years ago
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Juliette [100K]

Answer:

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