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Aleksandr-060686 [28]

3 years ago

5

the core of the earth is made of iron.if the core of the earth is about 10300 degrees Fahrenheit,why then is the core melting in

to a liquid

1 answer:

Citrus2011 [14]3 years ago

7 0

melting point iron less than 10300

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The fulcrum of a uniform 20-kg seesaw that is 4.0 m long is located 2.5 m from one end. A 30-kg child sits on the long end. Part

uranmaximum [27]

Answer:

57 kg

Explanation:

Mass of seesaw = 20 kg

Length of seesaw = 4 m

Mass of child on the longer end = 30 kg

The weight of the seesaw acts at the center i.e. 2m

The algebraic sum of moments of all forces about any point is zero, hence, using the fulcrum as the reference point:

[x * 9.8* 1.5] - [20 * 9.8* (2.5 - 2)] - [30 * 9.8 * 2.5] = 0

=> 14.7x = (20*9.8*0.5) + 735

14.7x = 98 + 735

14.7x = 833

=> x = 833/14.7

x = 57 kg

7 0

3 years ago

You are designing a manned submersible to withstand the pressure of seawater at the bottom of the Mariana Trench, which is one o

elena55 [62]

Answer:

110029941 Pa

311388.81857 N

286.48968 N

Explanation:

$P_0$ = Atmospheric pressure = 101325 Pa

$\rho$ = Density of seawater = 1029 kg/m³

h = Depth = 10900 m

g = Acceleration due to gravity = 9.81 m/s²

r = Radius = 3 cm

A = Area = $\pi r^2$

Gauge pressure

$P_g=\rho gh\\\Rightarrow P_g=1029\times 9.81\times 10900\\\Rightarrow P_g=110029941\ Pa$

The gauge pressure is 110029941 Pa

Net pressure at the given depth

$P=P_0+\rho gh\\\Rightarrow P=101325+1029\times 9.81\times 10900\\\Rightarrow P=110131266\ Pa$

Force is given by

$F=PA\\\Rightarrow F=110131266\times \pi 0.03^2\\\Rightarrow F=311388.81857\ N$

The force is 311388.81857 N

Now if P = 1 atm

$F=101325\times \pi 0.03^2\\\Rightarrow F=286.48968\ N$

The force is 286.48968 N

7 0

3 years ago

Atwood machine. A 20kg box and a 30kg crate are attached to the two ends of a massless string that passes over a massless fricti

Verdich [7]

Answer with Explanation:

We are given that

$m_1=20 kg$

$m_2=30 kg$

We have to find the acceleration of the system and the tension in the string.

$30g-T=30a$ ...(1)

$T-20g=20a$

$T=20a+20g$ ...(2)

Using equation (2) in equation (1)

$30g-(20a+20g)=30a$

$30g-20a-20g=30a$

$10g=30a+20a=50a$

$a=\frac{10g}{50}=\frac{10\times 9.8}{50}=1.96 m/s^2$

Where $g=9.8m/s^2$

Using the value of a in equation (2)

$T=20(a+g)=20(1.96+9.8)=235.2 N$

5 0

3 years ago

A 1000 kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at

Natali5045456 [20]

Answer:

0.21 SECONDS

Explanation:

THE CAR TRAVELS AT A SPEED OF 140M/S AND A DISTANCE AS THE PREVIOUS = 3M THEREFOR S=D/T, T=D/S= 3/140= 0.12 SEC

4 0

3 years ago

In polyphonic music, an independent voice is one that A. includes multiple melodic lines. B. isn't interesting enough to hold a

MaRussiya [10]

The answer to your question would be option (c)

3 0

3 years ago

Read 2 more answers