In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (
1 answer:
In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,
WATER:-
Mass :- 0.02 kg at 70°C
Specific Heat Of Water is 4,200 J/kg°C,
COPPER:-
MASS:- mass 0.16 kg at 15°C
Temperatures r according to the part !
what is the quantity of heat released per kg of water per 1°C fall in temperature?
Calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C.
Assuming that the heat released by water is entirely used to raise the temperature of calorimeter from 15°C to 45°C) calculate the specific heat capacity of copper.
It is the amount of the heat released by unit mass of the body per 1°C fall in temperature.
It is the amount of the heat absorbed by the unit mass of the body per 1°C rise in temperature
So quantity of heat released per kg of water per 1°C fall in temperature is equal to the specific heat of the water which is 4,200 J/kg°C,
MASS OF WATER --> 0.02 kg
INITIAL TEMPERATURE--> 70°C
FINAL TEMPERATURE--> 45°C
CHANGE IN TEMPERATURE--> (45-70)°C =(- 25)°C
SPECIFIC HEAT OF WATER--> 4200 J/ kg °C
NEGATIVE INDICATES THAT HEAT IS RELEASED BY THE BODY!
IT MEANS COOLING HAS BEEN TAKEN PLACED.
MASS OF COPPER :- 0.16 kg
INITIAL TEMPERATURE:- 15°C
FINAL TEMPERATURE:- 45°C
CHANGE IN TEMPERATURE--> (45-15)°C = 30°C
AMOUNT OF HEAT RELEASED BY WATER --> 2100 J ( From second part)
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Answer:
The answer to the question is;
The total potential energy of the mass on the spring when the mass is at either endpoint of its motion is 5.0255 Joules.
Explanation:
To answer the question, we note that the maximum speed is 2.30 m/s and the mass is 1.90 kg
Therefore the maximum kinetic energy of motion is given by
Kinetic Energy, KE =
Where,
m = Attached vibrating mass = 1.90 kg
v = velocity of the string = 2.3 m/s
Therefore Kinetic Energy, KE = ×1.9×2.3² = 5.0255 J
From the law of conservation of energy, we have the kinetic energy, during the cause of the vibration is converted to potential energy when the mass is at either endpoint of its motion
Therefore Potential Energy PE at end point = Kinetic Energy, KE at the middle of the motion
That is the total potential energy of the mass on the spring when the mass is at either endpoint of its motion is equal to the maximum kinetic energy.
Total PE = Maximum KE = 5.0255 J.