In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,
WATER:-
Mass :- 0.02 kg at 70°C
Specific Heat Of Water is 4,200 J/kg°C,
COPPER:-
MASS:- mass 0.16 kg at 15°C
Temperatures r according to the part !
what is the quantity of heat released per kg of water per 1°C fall in temperature?
Calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C.
Assuming that the heat released by water is entirely used to raise the temperature of calorimeter from 15°C to 45°C) calculate the specific heat capacity of copper.
It is the amount of the heat released by unit mass of the body per 1°C fall in temperature.
It is the amount of the heat absorbed by the unit mass of the body per 1°C rise in temperature
So quantity of heat released per kg of water per 1°C fall in temperature is equal to the specific heat of the water which is 4,200 J/kg°C,
MASS OF WATER --> 0.02 kg
INITIAL TEMPERATURE--> 70°C
FINAL TEMPERATURE--> 45°C
CHANGE IN TEMPERATURE--> (45-70)°C =(- 25)°C
SPECIFIC HEAT OF WATER--> 4200 J/ kg °C
NEGATIVE INDICATES THAT HEAT IS RELEASED BY THE BODY!
IT MEANS COOLING HAS BEEN TAKEN PLACED.
MASS OF COPPER :- 0.16 kg
INITIAL TEMPERATURE:- 15°C
FINAL TEMPERATURE:- 45°C
CHANGE IN TEMPERATURE--> (45-15)°C = 30°C
AMOUNT OF HEAT RELEASED BY WATER --> 2100 J ( From second part)
Answer:
s = 20 m
Explanation:
given,
mass of the roller blader = 60 Kg
length = 10 m
inclines at = 30°
coefficient of friction = 0.25
using conservation of energy
u = 9.89 m/s
Using second law of motion
ma =μ mg
a = μ g
a = 0.25 x 9.8
a = 2.45 m/s²
Using third equation of motion ,
v² - u² = 2 a s
0² - 9.89² = 2 x 2.45 x s
s = 20 m
the distance moved before stopping is 20 m