Answer:
A) 1568.60 Hz
B) 1437.15 Hz
Explanation:
This change is frequency happens due to doppler effect
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source
where
C = the propagation speed of waves in the medium;
Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;
Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.
A) Here the Source is moving towards the receiver(C-Vs)
and the receiver is standing still (Vr=0) therefore the observed frequency should get higher
B)Here the Source is moving away the receiver(C+Vs)
and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser
Answer:
g/cm³
Explanation:
From the question given above,
The y-axis is representing mass (g)
The x-axis is representing volume (cm³)
Unit of slope =?
Slope of a graph is simply defined as the change in y-axis divided by the change in x-axis. Mathematically it is expressed as:
Slope = change in y-axis (Δy)/change in x-axis (Δx)
Slope = Δy/Δx
Thus, with the above formula, we can obtain the unit used for measuring the slope as follow:
y-axis = mass (g)
x-axis = volume (cm³)
Slope =.?
Slope = Δy/Δx
Slope = mass (g) /volume (cm³)
Slope = g/cm³
Therefore, the derive unit used for measuring the slope is g/cm³
Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;
Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.
Answer;
=32.15 meters
Explanation;
Use the formula
s= ut+ 0.5 a (t)^2 to find out 's'
where s= distance traveled
u=initial velocity which is zero in this case
t= time taken to travel 's' distance
a=acceleration (due to gravity on moon i.e 1.62 m/s^2 )
Therefore;
S = 0.5 * 1.62 * 6.3 * 6.3
= 32.1489 meters
Thus; the crater is 32.15 meters deep.
