Three objects of uniform density—a solid sphere, a solid cylinder, and a hollow cylinder— are placed at the top of an incline (f
ig. cq10.13). they are all released from rest at the same elevation and roll without slipping. (a) which object reaches the bottom first
1 answer:
First you must make a free body diagram of each body to find the acceleration of each one. After you find the general formula of acceleration, you must replace the values of K for each body. (Assuming they all have the same mass). Finally, by replacing K, the body that gets the most acceleration will be the first to reach the bottom.I attached the solution.In this case the solid sphere reaches the bottom first.
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Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
