Answer:
Step-by-step explanation:
Start from left one first
12x & 70
Area as Sum= 12x+70
Area as Product = 12(x+5)
Right side
X & 4
Area as Sum= 5X+20
Area as Product = 5(X+4)
Answer:
um
Step-by-step explanation:
Answer:
The measure of angle θ is 7π/6. The measure of its reference angle is <u>210°</u>
and sin θ is <u>-1/2</u>.
Step-by-step explanation:
The correct question is:
<em>The measure of angle θ is 7π/6. The measure of its reference angle is ___</em>
<em>and sin θ is ___</em>
180° is equivalent to π radians. To transform 7π/6 radians to degrees, we have to use the following proportion:
180° / π radians = x° / (7π/6 radians)
x = (180/π) * (7π/6 radians)
x = 210°
And sin(210°) = -1/2
5x + 14 = 26
subtract 14 on both sides
5x = 26 - 14
5x = 12
Divide 5 on both sides
x = 12/5
x = 2.4
That's only to the nearest tenth. To make it to the hundreth, just add another 0 at the end. It doesn't change the value of it.
x = 2.40 is your final answer.
Answer:
20. AB = 42
21. BC = 28
22. AC = 70
23. BC = 20.4
24. FH = 48
25. DE = 10, EF = 10, DF = 20
Step-by-step explanation:
✍️Given:
AB = 2x + 7
BC = 28
AC = 4x,
20. Assuming B is between A and C, thus:
AB + BC = AC (Segment Addition Postulate)
2x + 7 + 28 = 4x (substitution)
Collect like terms
2x + 35 = 4x
35 = 4x - 2x
35 = 2x
Divide both side by 2
17.5 = x
AB = 2x + 7
Plug in the value of x
AB = 2(17.5) + 7 = 42
21. BC = 28 (given)
22. AC = 4x
Plug in the value of x
AC = 4(17.5) = 70
✍️Given:
AC = 35 and AB = 14.6.
Assuming B is between A and C, thus:
23. AB + BC = AC (Segment Addition Postulate)
14.6 + BC = 35 (Substitution)
Subtract 14.6 from each side
BC = 35 - 14.6
BC = 20.4
24. FH = 7x + 6
FG = 4x
GH = 24
FG + GH = FH (Segment Addition Postulate)
(substitution)
Collect like terms


Divide both sides by -3

FH = 7x + 6
Plug in the value of x
FH = 7(6) + 6 = 48
25. DE = 5x, EF = 3x + 4
Given that E bisects DF, therefore,
DE = EF
5x = 3x + 4 (substitution)
Subtract 3x from each side
5x - 3x = 4
2x = 4
Divide both sides by 2
x = 2
DE = 5x
Plug in the value of x
DE = 5(2) = 10
EF = 3x + 4
Plug in the value of x
EF = 3(2) + 4 = 10
DF = DE + EF
DE = 10 + 10 (substitution)
DE = 20