The time taken for the ball to fall a distance of 10feet is 1.25secs
Given the function modeled by the height expressed as:
f(t) =-16t² + 35
In order to determine the time taken by the all to fall a distance of 10 feet, hence;
f(t) = 10
10 = -16t² + 35
-16t² = 10 - 35
-16t² = -25
-t² = -25/16
t² = 25/16
t = √25/16
t = 5/4
t = 1.25secs
Hence the time taken for the ball to fall a distance of 10feet is 1.25secs
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Answer:
5.36
Step-by-step explanation:
Given that:
<BAD = <CAE, therefore, BD = EC
Let's take x to be the length of BD = EC
BD + DE + EC = BC
BC = 20,
BD = EC = x
DE ≈ 9.28
Thus,
x + 9.28 + x = 20
x + x + 9.28 = 20
2x + 9.28 = 20
Subtract 9.28 from both sides
2x + 9.28 - 9.28 = 20 - 9.28
2x = 10.72
Divided both sides by 2 to solve for x
BD ≈ 5.36
Answer:
-2(57+8) = 14 + 6x
step 1 -2 x 57 and -2 x 8 =
step 2 -114-16 = 14 + 6x
+16 +16
step 3 -114 = 30 + 6x
-30 -30
step 4 -144 = 6x
-144/6 6/6
x = -24
-2(5x + 8) = 14 + 6x
step 1 -2 x 5x and -2 x 8 =
-10x - 16 = 14 + 6x
step 2 -6x -6x
-16x -16 = 14
step 3 +16 +16
-16x = 30
step 4 -16/-16 30/-16
x= -15/8
Answer:
F
Step-by-step explanation:
1m = 100cm
0.8m = 100*0.8 = 80cm
AAS Angles A and D are one pair of congruent angles, then angles B and E are congruent because they are both right angles, following that you have line BC as congruent to EF so that is an angle, an angle, and a side so AAS
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