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3 years ago

How do these triangles compare?

Mathematics

2 answers:

alexandr402 [8]3 years ago

4 0

Answer:

B option. AB is larger than FD

Step-by-step explanation:

The rule which must be remembered here is:

The side opposite to the larger angle will be larger in measure. We have to compare two sides that are opposite to two angles 72 and 65.

So using the above rule we can say that side opposite to angle 72 will be greater in measure than the side opposite to 65.

The side opposite to 72 is AB and side opposite to 65 is FD.

Therefore, we can conclude that AB is larger in measure than FD, which makes option B as the correct answer,

kirza4 [7]3 years ago

4 0

<u>Answer:</u>

The correct answer option is AB is longer than FD.

<u>Step-by-step explanation:</u>

We are given two triangles, ΔABC and ΔDEF, where AC ≅ FE and BC ≅ DE.

One out of three angles is known for each triangle: ∠ACB = 72° and ∠DEF = 65° and we are to determine which of the statements is correct about AB and FD.

We know that the side opposite to the bigger angle is longer. Since ∠C = 72° is greater than ∠E, therefore side AB is longer than FD.

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A student concluded that has infinitely many solutions. Which statement BEST describes the student’s conclusion?

Nastasia [14]

What's the equation?

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3 years ago

write the equation of the line (in slope-intercept form) that passes through the points (2,3 and (5,7)

AfilCa [17]

Answer:

The answer to your question is y = 4/3x + 1/3

Step-by-step explanation:

Data

Point A = (2, 3)

Point B = (5, 7)

Process

1.- Calculate the slope

x1 = 2 y1 = 3

x2 = 5 y2 = 7

m = (y2 - y1)/(x2 - x1)

- Substitution

m = (7 - 3)/(5 - 2)

- Slope

m = 4/3

2.- Find the equation of the line

y - y1 = m(x - x1)

y - 3 = 4/3(x - 2)

y - 3 = 4/3x - 8/3

y = 4/3x - 8/3 + 3

y = 4/3x - 8/3 + 9/3

y = 4/3x + 1/3

8 0

4 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Graph f(x)=4x^3-4x-2

maw [93]

Answer:

minimum: ( $\frac{\sqrt{3} }{3} , -\frac{8\sqrt{3} }{9}-2$ )

maximum: (- $\frac{\sqrt{3} }{3} , \frac{8\sqrt{3} }{9}-2$ )

vertical intercept: (0 , -2)

Step-by-step explanation:

3 0

3 years ago

When you divide , we are

fomenos

Could you be a little more specific.

5 0

4 years ago

Read 2 more answers