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Ymorist [56]
3 years ago
9

Find the 64th term of the following arithmetic sequence. 8,11,14,17

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer: 197

Step-by-step explanation:

The nth term is 3n+5

so the 64th term will be

(3 x 64)+5

192+5

= 197

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A 30-mile segment of road needs to be paved. 6 miles have already been completed. The paving crew can complete 3 miles of paving
wariber [46]

Answer: 8 days

Step-by-step explanation:

6 miles has been paved already.

Number of miles left = 30 - 6

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If they are paving at 3 miles a day, the days they will take to finish is:

= 24/3

= 8 days

5 0
3 years ago
Read 2 more answers
Can someone help me with this question please.
galina1969 [7]

Answer:

6, 8, and 10.

Step-by-step explanation:

You could work this out with the pythagorean theorem, by proving that 6^2, 36, plus 8^2, 64, equals 100. The fastest way, however, is to use pythagorean triples. These are predetermined sets of numbers that work as side lengths for right triangles. The first two are 3, 4, and 5, which form a right triangle, and 6, 8, and 10, shown here.

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2 years ago
Please help me....people are just using my points and im running out.....please help me!!
storchak [24]

Answer

I think that c would equal 4

Step-by-step explanation:

If you need the explanation, here it is:

When looking at the y part of the answer, you can see it goes up by three and that it is missing a point. This means that if the equation is linear, it goes up by one. Hope that's right!!

5 0
2 years ago
Plz help duke for 10 points
BaLLatris [955]

Answer

A) 2(4+5)

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B) 2(10+2)

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D) 10*2

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7 0
3 years ago
Does Cos (x+y)=cosx+cosy? Or not?
dangina [55]
\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
\boxed{cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})}\impliedby notice
\\ \quad \\
cos({{ \alpha}} - {{ \beta}})= cos({{ \alpha}})cos({{ \beta}}) + sin({{ \alpha}})sin({{ \beta}})
4 0
3 years ago
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