Answer:
- C = 0.97m
- $1164 for 1200 miles
- 845 miles for $820
Step-by-step explanation:
Given a car's cost of operation is $485 for 500 miles, you want an equation relating cost for m miles, and solutions to that equation for 1200 miles, and for a cost of $820.
<h3>Cost per mile</h3>
The cost per mile is found by dividing the cost by the associated number of miles:
$485/(500 mi) = $0.97 /mi
<h3>Equation</h3>
The equation for the cost will show the cost as the cost per mile multiplied by the number of miles:
C = 0.97m . . . . . where C is cost in dollars for m miles driven
<h3>1200 miles</h3>
The cost for driving $1200 miles will be ...
C = 0.97(1200) = $1164
The cost of driving 1200 miles is $1164.
<h3>$820</h3>
The number of miles that can be driven for a cost of $820 is ...
820 = 0.97m
m = 820/0.97 = 845.36
About 845 miles are driven for a cost of $820.
2L + 2W = 36
2(3+2W) + 2W = 36
6 + 4W + 2W = 36
6W + 6 = 36
-6 = -6
6W=30
W= 30/6 = 5 L= 3 + 2W = 3 +2 (5) = 3 +10= 13
Width is 5
Length is 13
Let x be the <span>heights of a maple tree and y be the height of the cherry tree.
We know:
</span>
<span>The new ratio is obtained like this:
</span>
.
From the above equation we get
.
then
Solving the above equation for y we get:
So
So the first tree is (400-160=240) more taller than cherry tree.
3 39/40 = 3.975
3 19/20 = 3.95
3 1/2 = 3.5
least to greatest : 3 1/2, 3 19/20, 3 39/40
Answer:
(b+x)(−b+x)(b−2)
Step-by-step explanation:
Factor bx2 + 2b2 − b3 − 2x2 − b3 + bx2 + 2b2 − 2x2 = (b+x)(−b+x)(b−2)
hope this helps! :)
