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tiny-mole [99]
3 years ago
10

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
Mathematics
1 answer:
777dan777 [17]3 years ago
5 0
She has a probability of 7/11
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The following are the last 7 days adjusted closing stock prices (in $) for Citigroup: 22, 25, 20, 15, 40, 55, 28 A) Compute the
son4ous [18]

Answer:

(A) The 25th percentile is 20.

(B) The mean of the data set is 20 and the median of the data set is 25. The data set is left-skewed.

Step-by-step explanation:

The data set arranged in ascending order is:

S = {15, 20, 22, 25, 28, 40, 55}

(A)

Compute the 25th percentile as follows:

25^{th} \text{Percentile}=[\frac{n+1}{4}]^{th}obs.\\\\=[\frac{7+1}{4}]^{th}obs.\\\\=2^{nd}obs.\\\\=20

Thus, the 25th percentile is 20. This value implies that exactly 25% of the observations are less than 20.

(B)

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Compute the median as follows:

For a set with odd number of observations, the median value if the middle value.

The middle value is 25.

Thus, the mean of the data set is 20 and the median of the data set is 25.

The Mean < Median.

This implies that the data set is left-skewed.

4 0
3 years ago
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