Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
Please see the attached picture ! :D
-------- HappY LearninG <3 ----------
Point B is located at point (4, -2)
Answer:
The 24 pack for 24 dollars!
Step-by-step explanation:
This is because you see that 12 is 1/2 of 24 and if you do 13x2 you get 26$ so for the 12 pack if you double it you will be paying 2$ more than if you got the OG 24 pack
Mary<span> is 2x = 2*12 = </span>24 years old<span>.</span>