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2 years ago

2 (-4x + 2) What does this equal

Mathematics

2 answers:

Yuri [45]2 years ago

7 0

Answer:

-8x+4

Step-by-step explanation:

Makovka662 [10]2 years ago

5 0

Answer:

-8x+4

Step-by-step explanation:

You might be interested in

What is the circumference of the circle? (use 3.14 for pi)

Alina [70]

Step-by-step explanation:

$Circumference = d\pi$

$Circumference = (18) \pi$

$Circumference = 56.52$

The circumference of the circle is 56.52 km which is letter choice B.

3 0

2 years ago

Read 2 more answers

S 8,000 a good estimate for the sum of 3,816 and 467?

Damm [24]

Answer:

it is not a good estimate.

Step-by-step explanation:3816 can be rounded to 4000 and 467 can be rounded to 500. Adding 4000+500 gives 4500, which isn't near 8000.

i hoped this helped :)

7 0

2 years ago

Please help and explain!

Scrat [10]

K is the slope of the line formed by connecting the points.
Use slope formula:
$\frac{y_2 - y_1}{x_2 - x_1}$
where the 2 points are the end points of the line (First and last going Left to right)
$(x_1,y_1) = (2,7) \\ (x_2,y_2) = (8,28)$
Substitute into slope formula
$k= \frac{28-7}{8-2} = \frac{21}{6} = \frac{7}{2}$
You can check if this is correct by going back to graph and going "up 7" and "over 2" to get from one point to the next.

5 0

2 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

2 years ago

Bonds from the city of tavel gorge worth $1,000 each are selling at 110.611. if sean wishes to purchase three such bonds, how mu

umka2103 [35]

The amount that will be expected to be paid for the bonds that are bought will be C. $3,318.33

<h3>How to calculate the amount of bonds?</h3>

From the information given, the bonds from the city of tavel gorge worth $1,000 each are selling at 110.611 and Sean wishes to purchase three such bonds.

Therefore, the amount for the bonds will be:

= 1110.611 × 3

= 3,318.33

In conclusion, the correct option is C.

Learn more about bonds on:

brainly.com/question/2775110

#SPJ4

8 0

1 year ago