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OLEGan [10]
3 years ago
13

Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet

wide by 6 feet long. Which quadratic equation can be used to determine the thickness of the frame, x? (5 points)
Mathematics
2 answers:
fomenos3 years ago
5 0

Answer:

4x² + 22x − 1 = 0

Valentin [98]3 years ago
4 0

Answer:

4x² + 22x − 1 = 0

Step-by-step explanation:

Start off with the standard formula to finding area with polynomials and quadratic functions.

(2x + 5)(2x + 6)

Work out like a normal binomial.

4 + 22x + 30 - 31

(You're subtracting 31 to take out the minimum of what the frame has to be)

4 + 22x - 1 = 0

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7 0
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mafiozo [28]

Answer:

2

Step-by-step explanation:

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4 0
3 years ago
Formula for finding perimeter/circumference of major sector<br> plz no links<br> in a hurry
Rainbow [258]

Answer:

C = 2πr or C = πd

Step-by-step explanation:

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3 0
3 years ago
What's a number that has exactly three factors???
Kay [80]
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3 0
3 years ago
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
beks73 [17]
So, how much acid is there in 6 gallons?  well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it?  well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it?  (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\&#10;&------&------&------\\&#10;\textit{pure acid}&x&1.00&x\\&#10;\textit{20\% sol'n}&6&0.20&1.2\\&#10;------&------&------&------\\\&#10;mixture&y&0.90&0.9y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+6=\boxed{y}\\&#10;x+1.2=0.9y\\&#10;----------\\&#10;x+1.2=0.9\left( \boxed{x+6} \right)&#10;\end{cases}&#10;\\\\\\&#10;x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2&#10;\\\\\\&#10;x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}
3 0
3 years ago
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