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3 years ago

13

A standing wave is produced by plucking a string. the points along the plucked string that appear not to be vibrating are produc

ed by ____________________ interference.

2 answers:

qaws [65]3 years ago

7 0

Answer:

The answer is destructive, if you are able to, can I get brainly.

Explanation:

Rasek [7]3 years ago

4 0

The answer is destructive

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Suppose there are single-particle energy eigenvalues of 0, e, 2.::, and 3.:: which are non-degenerate. A total of 6.0 is to be s

elena-14-01-66 [18.8K]

Answer:

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Explanation:

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3 years ago

Please expert solve this

777dan777 [17]

Explanation:

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3 years ago

Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ an

Alex

Answer:

0.33 Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33 Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: $\frac{V^2}{R}$ which gives:

4^2 / 2 = 8 Watts

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3 years ago

An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6

lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

$I = \frac{P_{avg}}{A}$

$I = \frac{P_{avg}}{4\pi r^2}$

$I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m$

$I = 6.529*10^{-6}W/m^2$

The amplitude of electric field at the receiver is

$I = \frac{E_{max}^2}{2\mu_0 c}$

$E_{max}= \sqrt{2I\mu_0 c}$

The amplitude of induced emf by this signal between the ends of the receiving antenna is

$\epsilon_{max} = E_{max} d$

$\epsilon_{max} = \sqrt{2I \mu_0 cd}$

Here,

I = Current

$\mu_0$ = Permeability at free space

c = Light speed

d = Distance

Replacing,

$\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}$

$\epsilon_{max} = 0.05434V$

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

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4 years ago

Difference between male and female gamete

Inga [223]

Answer:

The male gamete is smaller in comparison to that of the female gamete.

The male gamete is conical from the front while the female gamete is spherical.

The cytoplasm in the male gamete is less in comparison to that of the female gamete.

The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.

The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.

The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.

Explanation:

5 0

3 years ago

Read 2 more answers