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lilavasa [31]
4 years ago
13

A standing wave is produced by plucking a string. the points along the plucked string that appear not to be vibrating are produc

ed by ____________________ interference.
Physics
2 answers:
qaws [65]4 years ago
7 0

Answer:

The answer is destructive, if you are able to, can I get brainly.

Explanation:

Rasek [7]4 years ago
4 0
The answer is destructive

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What happens when light enters a pair of glasses
alexdok [17]

Answer:

It refracts when it hits the glass.

6 0
3 years ago
You estimate the radius of the big wheel to be 19 m
posledela
Explanation:

first, find the circumference of the wheel by using the formula 2(pi)(r):

2(pi)(19) = 119.380521

divide by 25 secs

119.380521/25 = 4.77522083

round to the nearest tenth is 4.8, so the speed is 4.8mm/sec
7 0
4 years ago
S= 1/2(V f + V I )t solve for V f <br><br> show me how
vaieri [72.5K]
<span>S= 1/2(V f + V I )t solve for V f 
2s/t=Vf+Vi
</span><span>2s/t-Vi=Vf</span>
8 0
4 years ago
A small bouncy ball with a momentum of 8 kg∙m/s to the left approaches head-on a large door at rest. The ball bounces straight b
vlada-n [284]

Answer:

-14 kg m/s

Explanation:

Taking the  direction "to the left" as positive direction, the initial momentum of the ball is

p1 = +8 kg m/s

while the final momentum is

p2 = -6 kg m/s

so the change in momentum is

\Delta p = p_2 - p_1 = -6kg m/s - (8 kg m/s) = -14 kg m/s

According to the impulse theorem, the impulse exerted on the ball is equal to the change in momentum of the ball, so:

I_1 = -14 kg m/s (which means 14 kg m/s to the right)

While the impulse that the ball exerted on the ball is equal and opposite in direction, so:

I_2 = + 14 kg m/s (which means towards the left)

4 0
4 years ago
A rock is thrown upward with a velocity of 18 meters per second from the top of a 38 meter high cliff, and it misses the cliff o
Roman55 [17]

The rock would be at a point 12 m from water at a time <u>4.8 s</u>.

Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

y= -38m- (-12 m)=-26 m

Use the equation of motion,

y=ut +\frac{1}{2} at^2

The rock falls under the acceleration due to gravity, directed down wards.

Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

y=ut +\frac{1}{2} at^2\\ (-26 m)=(18m/s)t+\frac{1}{2}(-9.8m/s^2)t^2

Solve the quadratic equation for t.

t=\frac{(18m/s)(+/-)\sqrt{(18m/s)^2-4(4.9m/s^2)(-26m)} }{2(4.9m/s^2)}

Taking only the positive value,

t=\frac{(18 m/s)+(28.87 m/s)}{9.8 m/s^2)} \\ t=4.78 s

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.

8 0
3 years ago
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