3 years ago

PLEASE HELP and actually help plz

1 answer:

3 0

Answer:

iEvaluate for $x=2.$Evaluate for $x=2.$Evaluate for $x=2.$Evaluate for $x=2.$Evaluate for $x=2.$Evaluate for $x=2.$Evaluate for $x=2.$

Explanation:

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3 years ago

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Explanation:

Given that,

Inside pressure $P_{in}= 1.90\times10^{5}\ Pa$

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Using formula of force

$F_{net}=F_{in}-F_{out}$

$F_{net}=(P_{in}-P_{out})A$

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Put the value into the formula

$F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}$

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3 years ago

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In any case, your mass would be<em> 68 kg </em>no matter what

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2 years ago