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AlekseyPX
3 years ago
13

PLEASE HELP and actually help plz

Physics
1 answer:
frutty [35]3 years ago
3 0

Answer:

iEvaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)

Explanation:

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While performing an experiment, the student creating the data table is not sure if a measurement from the experiment is a vector
marin [14]

Before coming into conclusion first we have to understand both scalar and vector .

A scalar quantity is a physical quantity which has only magnitude for it's complete specification.

A vector quantity is that physical quantity which not only requires magnitude but also possesses direction for it's complete specification.

So the most important factor that differentiate vector from scalar is the direction.

As per the question the student is doing an experiment where he is recording the data obtained during the process.

In order to arrange them in data table, he should ask about the direction of the quantity under consideration.


Hence the correct option is the third option(C)i.e does the measurement include direction?




7 0
3 years ago
Read 2 more answers
A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver n
satela [25.4K]

Answer:

a) t1 = v0/a0

b) t2 = v0/a0

c) v0^2/a0

Explanation:

A)

How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0

Vf = 0

Vf = v0 - a0*t

0 = v0 - a0*t

a0*t = v0

t1 = v0/a0

B)

How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.

at this point

U = 0

v0 = u + a0*t

v0 = 0 + a0*t

v0 = a0*t

t2 = v0/a0

C)

The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.

t1 = t2 = t

Distance covered by the train = v0 (2t) = 2v0t

and we know t = v0/a0

so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0

now distance covered by car before coming to full stop

Vf2 = v0^2- 2a0s1

2a0s1 = v0^2

s1 = v0^2 / 2a0

After the full stop;

V0^2 = 2a0s2

s2 = v0^2/2a0

Snet = 2v0^2 /2a0 = v0^2/a0

Now the separation between train and car

= (2v0^2)/a0 - v0^2/a0

= v0^2/a0

8 0
4 years ago
An unconformity between two sedimentary layers is classified as a disconformity. <br> true or false
Strike441 [17]

Answer:

hii there

The correct answer is True

Explanation:

Hope it helps

have a nice day :)

3 0
3 years ago
Mike rides his motorcycle North at an average speed of 20 meters/second for 50 seconds,
tia_tia [17]
He rode his bike 0.4 miles because you divide 20 by 50
5 0
3 years ago
I need help with this​
insens350 [35]

Answer:

distance = 32 kilometers

displacement = 0 kilometers

Explanation:

they traveled 15 km to and back which would mean the distance they traveled is 32 km. but the displacement would still be 0 because their starting and ending points are the same.

7 0
3 years ago
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