Answer:
1)
75 kmh⁻¹
2)
75 kmh⁻¹
Explanation:
1)
= Speed of train from station A to station B = 80 kmh⁻¹
= distance traveled from station A to station B
= time of travel between station A to station B
we know that


= distance traveled from station B to station C
= Speed of train from station B to station C = 60 kmh⁻¹

Total distance traveled is given as

Total time of travel is given as

Average speed is given as

Given that :

So

2)
= Speed of train from station A to station B = 80 kmh⁻¹
= time of travel between station A to station B
= distance traveled from station A to station B
we know that


= distance traveled from station B to station C
= Speed of train from station B to station C = 60 kmh⁻¹
= time of travel for train from station B to station C
we know that


Total distance traveled is given as

Total time of travel is given as

Average speed is given as

Given that :

So
