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lorasvet [3.4K]
4 years ago
11

1 Apply Look around you to an object in motion. Describe the motion by discussing its position and direction of motion in relati

on to a reference point. Then explain how you could determine the object's speed.

Physics
1 answer:
luda_lava [24]4 years ago
5 0
Most of the problem depends on which object you observe. For the speed, take the absolute value of the derivative of the polynomial interpolation of position verses time.
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A sound wave has a speed of 340 m/s and a frequency of 1000 hz. The period of the sound is closest to?
harina [27]
<h2>Relationship Between Frequency and Period</h2>

The frequency and the period are inversely proportional.

f=\dfrac{1}{T} where T is the period

<h2>Solving the Question</h2>

We're given:

  • <em>v</em> = 340 m/s
  • <em>f</em> = 1000 Hz

Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:

T=\dfrac{1}{1000}

<h2>Answer</h2>

T=\dfrac{1}{1000}

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2 years ago
According to Newton’s first law of motion, when will an object at rest begin to move?
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Newton's first law of motion says something like "An object remains
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If an object changes from rest to motion, that's definitely a change
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8 0
4 years ago
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A moving walkway has a speed of 0.9 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of
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B or .2 East is the correct answer
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3 years ago
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A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between p
Hitman42 [59]
Note : Be careful with speed and velocity, even the formula is same that v =  \frac{x}{t}

1. If we would like to find the velocity, we must calculate the distance from initial to final, x_{f} -  x_{i} = (delta)x,

2. If we would like to find the speed, we must calculate the total distance that travelled (x_{total}.

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Answer:

MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...

Explanation:

TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....

TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..

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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

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