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3 years ago

14

Can someone please answer. There is one problem. There's a picture. Thank you!

1 answer:

Viktor [21]3 years ago

6 0

To find the volume of a triangular prism, you can find the area of the base triangle, and multiply that value by the height of the prism.
So let's first find the area of the base triangle (which is its base times height, divided by 2):
$\frac{b \times h}{2} = \frac{4.5\times3}{2} = \frac{13.5}{2} =6.75$

Then, multiply this value by the height of the prism, which will give you the prism's volume:
$6.75 \times 9=60.75$

Your answer is 60.75 miles³, or option 2.

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When Donetle stands at point R, he is 1000 feet from point S at the base of a cliff.

statuscvo [17]

Answer:

364 is right answer

Step-by-step explanation:

ST = 1000× tan

364 ft

8 0

2 years ago

I’m soooo confused someone please helppppp!!

Ganezh [65]

Answer:

m>-5

Why? because the arrow shows -5 less then any number going right

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7 0

3 years ago

The width of a rectangle is two cm less than 8 times the length. The perimeter is 88 cm. What is the width and length of the rec

kati45 [8]

Let's the length to be x,

then the width is 8x - 2.

Perimeter of a rectangle = 2*Width + 2*Length

Perimeter of the rectangle = 2(8x-2) + 2x = 16x - 4 + 2x = 18x - 4

Ar the same time, Perimeter of the rectangle = 88.

So, we can write

18x - 4 = 88

18x = 84

9x=42

x= 42/9 cm (length) or ≈ 4.67 cm (length)

8x - 2 = 8*42/9 - 2 ≈ 35.33 cm (width)

6 0

3 years ago

If x2 = 30. what is the value of x?

kirza4 [7]

Answer:

5.4772255750516 that's if it is x squared

4 0

3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

3 years ago