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OlgaM077 [116]
4 years ago
14

A shaft undergoing torsional vibrations is held fixed at one end, and it has attached at the other end a disk with a rotary iner

tia of 4 kg m2about the rotational axis. The rotary inertia of the shaft is negligible compared to that of the disk, and the torsional stiffness of the shaft is 8 Nm /rad. The disk is placed in an oil housing, and the associated dissipation is modeled by using an equivalent torsional viscous damper with damping coefficient ct. What should the value of ctbe so that the system is critically damped?.
Physics
1 answer:
Elan Coil [88]4 years ago
4 0

Answer:

ct = 11.31 N.m.s/rad

Explanation:

Given that

I=4 \ kg m^2

Torsional stiffness  ,K= 8 Nm/rad

As we know damping coefficient ct (critical )given as

In simple spring mass system critical damping coefficient given as

ct=2\sqrt {m.K}

In  torsional system critical damping coefficient given as

ct=2\sqrt {I.K}

Now by putting the values

ct=2\sqrt {I.K}

ct=2\sqrt {4\times 8}

ct = 11.31 N.m.s/rad

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A satellite is orbiting earth at a distance of 35.0 kilometers. The satellite has a mass of 500 kilograms. What is the force bet
Alika [10]

Answer:

F = 4856.32 N

Explanation:

Given,

A satellite is orbiting earth at a distance from Earth surface, h = 35000 m

The mass of the satellite, m = 500 Kg

The radius of the Earth, R = 6.371 x 10⁶ m

The mass of the Earth, M = 5.972 x 10²⁴ Kg

The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²

The force between the Earth and the satellite is given by the formula

                                    F = GMm/(R+h)²  N

Substituting the values in the above equation

        F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²

                                        = 4856.32 N

Hence,  the force between the planet and the satellite is, F = 4856.32 N

5 0
3 years ago
A wheel has a constant angular acceleration of 1.8 rad/s2. During a certain 4.0 s interval, it turns through an angle of 45 rad.
tankabanditka [31]

Answer:

4.25 s

Explanation:

Given:

angular acceleration'α'=  1.8 rad/s²

angle 'θ'= 45 rad

time 't'= 4s

initial angular velocity 'w_{o}'=0rad^{-1}

as we know that,

θ= w_{1}t + \frac{1}{2} \alpha t^{2}

45 = 4 w_{1} + (0.5 x 1.8 x 16)

45- 14.4 = 4 w_{1}

30.6 = 4 w_{1}

w_{1}= 7.65 rad^{-1}

Next is to find t by using the equation

w_{1} =  w_{o} + \alpha t_{1}

7.65= 0 + (1.8)t_{1}

t_{1}= 7.65/1.8

t_{1}= 4.25 s

Therefore, At the start of 4s interval the motion is at 4.25 second

7 0
4 years ago
The table below shows two types of electromagnetic waves and three random applications of electromagnetic waves.
Musya8 [376]

Answer:

a. Microwaves—3 and infrared waves—1

Explanation:

Microwaves and infrared waves are both part of the electromagnetic spectrum, but they have different frequency and wavelength.

In particular:

- Microwaves are long-wavelength electromagnetic waves, with wavelength between 1 mm and 1 m. Their wavelength is longer than visible light

- Infrared waves are also long-wavelength electromagnetic waves, but their wavelength is shorter than microwaves: between 700 nm and 1 mm. Their wavelength is also longer than visible light.

The two types of waves are also used for different purposes. In particular:

- Infrared waves are emitted by any hot object, and their intensity depends on the temperature of the object. Therefore, they are used in astronomy to show the heat released by astronomical objects (option 1)

- Microwaves are used to study the Cosmic Microwave Background (CMB). This is electromagnetic radiation that permeates the whole universe, and its wavelength depends inversely on the local temperature. Therefore, areas with longer wavelength have lower temperature, and viceversa. Therefore, microwaves are used to measure temperature differences in space (option 3).

7 0
3 years ago
A runner runs a 5k race (3.1 miles) at a rate of 6.7
4vir4ik [10]

Answer:monkey

Explanation:

5 0
4 years ago
• 2. A 70 kg man on a 100 kg boat throws a ball. The boat moves backwards 5 meters in 10 seconds. What is
Kipish [7]

Answer:

0.5 m/sec

Explanation:

v=S÷t

 =5÷10

v=0.5 m/sec

6 0
3 years ago
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