A 6 kg block is released from rest at the top of an incline, as shown above, and slides to the bottom. The incline is 1.97 m lon
g, is inclined at an angle of 29.4°, and the coefficient of kinetic friction between the block and the incline is 0.21. a. Calculate the normal force the incline puts on the block.
where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.
The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.
<span>The electrons need to migrate from a region of lower electric potential to a region of higher electric potential. This flow of electrons is known as electron current (which is contrary to the widely-accepted perspective of conventional current).</span>
