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allsm [11]
3 years ago
14

4. Kamini uses a thick blanket for sleeping during cold weather. What is the function of the blanket? Explain your answer.​

Physics
2 answers:
aniked [119]3 years ago
7 0

Answer:

The function of the blanket is to provide warmth to Kamini, since the weather is cold they use a thick blanket.

Explanation:

Helga [31]3 years ago
6 0

Answer:

the function of the blanket is to keep Kamins warm so he wouldn't get cold

Explanation:

the thick layer of the material acts as a body protector from the cold weather

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For the bird moving in a straight line, the kinetic energy is one-half the product of the mass and the square of the speed: Ek=12mu2.

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What is the magnitude of the force a 25 mC charge exerts on a +2.5 mC charge 16 cm away?
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A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
Tju [1.3M]

Answer:

v = 2.85 m/s

Explanation:

By the law of similarity of the triangle we can say

\frac{height\: of\: man}{distance\: of \: man\: from \: spotlight} = \frac{height \:of \:image}{distance\: of \:wall\: from\: spotlight}

here we know that

height of man = 2 m

let the distance of man from spotlight = x

distance of wall from spotlight = 12 m

height of image is let say "y"

so we will have

\frac{2}{x} = \frac{y}{12}

y = \frac{24}{x}

now we have

\frac{dy}{dt} = \frac{24}{x^2}\frac{dx}{dt}

here we know

\frac{dx}{dt} = speed = 1.9 m/s

x = 4 m

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\frac{dy}{dt} = \frac{24}{4^2}(1.9)

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8 0
4 years ago
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7 0
3 years ago
Read 2 more answers
One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s
baherus [9]

Given that,

Central maximum = 1 cm

Distance from the window shade to the wall =4 m

We know that,

The visible range of the sun light is 400 nm to 700 nm.

(a). We need to calculate the average wavelength

Using formula of average wavelength

\lambda_{avg}=\dfrac{\lambda_{1}+\lambda_{2}}{2}

Put the value into the formula

\lambda_{avg}=\dfrac{400+700}{2}

\lambda_{avg}=550\ nm

(b). We need to calculate the diameter of the pinhole

Using formula for diameter

w=\dfrac{2.44\lambda L}{D}

D=\dfrac{2.44\lambda L}{w}

Put the value into the formula

D=\dfrac{2.44\times550\times10^{-9}\times4}{1\times10^{-2}}

D=0.537\ mm

Hence, (a). The average wavelength 550 nm.

(b). The diameter of the pinhole is 0.537 mm.

7 0
4 years ago
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