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3 years ago

Question 1 (1 point)

Mathematics

2 answers:

viktelen [127]3 years ago

7 0

The answer is 12.0182

KatRina [158]3 years ago

5 0

Answer:

97.2

Step-by-step explanation:

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HURRY HURRY HELP MEeeeee

melisa1 [442]

Answer:

dividing by 100

Step-by-step explanation:

6 0

3 years ago

If all 108 people take 2 biscuits, how many biscuits will you need?

grigory [225]

Answer:

216

Step-by-step explanation:

108 x 2 = 216

7 0

3 years ago

Read 2 more answers

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

70 divided by 10 - 3 + 1 = 11 where to put parentheses

Aleonysh [2.5K]

Answer:

70/(10-3)+1=11

Step-by-step explanation:

simplify

70/(7)+1=11

10+1=11

11=11

6 0

3 years ago

Read 2 more answers

It would mean a lot.

LUCKY_DIMON [66]

First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.

Formula to find distance given two points.

Square root (X2 - X1)^2 + (Y2 - Y1)^2

Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)

Xa goes into X2 and Xb goes into X1

(3 - (-1))^2

Ya goes into Y2 and Yb goes into Y1

(-4 - 3)^2

Square root (3 - (-1))^2 + (-4 - 3)^2

Square root (4)^2 + (-7)^2

Square root 16 + 49

Square root 65

= 8.06

The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.

6 0

3 years ago