Answer:
Circuit 4
Explanation:
To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:
For circuit 1:
Resistance (R) = 0.5 ohms
Voltage (V) = 20 V
Current (I) =?
V = IR
20 = I × 0.5
Divide both side by 0.5
I = 20 / 0.5
I = 40 A
For circuit 2:
Resistance (R) = 0.5 ohms
Voltage (V) = 40 V
Current (I) =?
V = IR
40 = I × 0.5
Divide both side by 0.5
I = 40 / 0.5
I = 80 A
For circuit 3:
Resistance (R) = 0.25 ohms
Voltage (V) = 40 V
Current (I) =?
V = IR
40 = I × 0.25
Divide both side by 0.25
I = 40 / 0.25
I = 160 A
For circuit 4:
Resistance (R) = 0.25 ohms
Voltage (V) = 60 V
Current (I) =?
V = IR
60 = I × 0.25
Divide both side by 0.25
I = 60 / 0.25
I = 240 A
SUMMARY
Circuit >>>>>> Current
1 >>>>>>>>>>> 40 A
2 >>>>>>>>>>> 80 A
3 >>>>>>>>>>> 160 A
4 >>>>>>>>>>> 240 A
From the above calculation, circuit 4 has the greatest electric current.
Answer:
The atomic number of Selenium is 34. This means that Selenium possesses 34 electrons.
The atomic number of Aluminium is 13. This means that Aluminium has 13 electrons.
Hence, there is a difference of 21 between the number of electrons in an atom of selenium and the number of electrons in an atom of aluminium.
Selenium has 6 electrons in it's outer most shell whereas aluminium has 3 electrons in its outer most shell. As a result, aluminium will have a greater tendency to lose one of its outer most electrons to become stable.
By atomic radius, the bottom left
<span>B) N2(g) + 3H2(g) → 2NH3(g)
</span>I hope this helps :)
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An orbital is the most probable location of an electron. This is because you can't pinpoint the exact location of an electron because as soon as you do it will have moved again, so orbitals are used to find the probability of where a certain electron is.
