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o-na [289]
2 years ago
10

Use the information in the table about four different electric circuits to answer the question

Chemistry
1 answer:
ycow [4]2 years ago
8 0

Answer:

Circuit 4

Explanation:

To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:

For circuit 1:

Resistance (R) = 0.5 ohms

Voltage (V) = 20 V

Current (I) =?

V = IR

20 = I × 0.5

Divide both side by 0.5

I = 20 / 0.5

I = 40 A

For circuit 2:

Resistance (R) = 0.5 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.5

Divide both side by 0.5

I = 40 / 0.5

I = 80 A

For circuit 3:

Resistance (R) = 0.25 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.25

Divide both side by 0.25

I = 40 / 0.25

I = 160 A

For circuit 4:

Resistance (R) = 0.25 ohms

Voltage (V) = 60 V

Current (I) =?

V = IR

60 = I × 0.25

Divide both side by 0.25

I = 60 / 0.25

I = 240 A

SUMMARY

Circuit >>>>>> Current

1 >>>>>>>>>>> 40 A

2 >>>>>>>>>>> 80 A

3 >>>>>>>>>>> 160 A

4 >>>>>>>>>>> 240 A

From the above calculation, circuit 4 has the greatest electric current.

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Explanation:

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5 0
3 years ago
A 17.6-g sample of ammonium carbonate contains ________ mol of ammonium ions.
postnew [5]
These problems are a bit interesting. :)

First let's write the molecular formula for ammonium carbonate. 

NH4CO3 (Note! The 4 and 3 are subscripts, and not coefficients)

17.6 gNH4CO3

Now to convert to mol of one of our substances we take the percent composition of that particular part of the molecule and multiply it by our starting mass. This is what it looks like using dimensional analyse. 

17.6 gNH4CO3 * (Molar Mass of NH4 / Molar Mass of NH4CO3)

Grab a periodic table (or look one up) and find the molar masses for these molecules! Well. In this case I'll do it for you. (Note: I round the molar masses off to two decimal places)

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Now just take the molar mass we found to convert that amount into moles!

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Explanation:

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