<span>The American Council for an Energy-Efficient Economy works to (c) </span>invest in clean energy technologies that will strengthen the economy.
Their aim is to promote energy efficiency which will ultimately benefit the economy and the environment.
25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.
The equation of the reaction is;
NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)
We can use the titration formula;
CAVA/CBVB = NA/NB
CA= concentration of acid
VA = volume of acid
CB = concentration of base
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
CB = 0.010 M
VB = 50.0 ml
CA = 0.50 M
VA = ?
NA = 1
NB = 1
Substituting values;
CAVANB = CBVBNA
VA = 0.010 × 50.0 × 1/ 0.50 × 1
VA = 1 ml
Since the total volume of acid used is 1 ml and each drop contains 0.040 ml
The number of drops required is 1ml/0.040 ml = 25 drops
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Answer:
Lead (II) Sulfate
Explanation:
Don't forget to add the (II) marking indicating that lead has a charge of 2+ (because Sulfate has a charge of 2-, balancing the ion).
Answer: five carbon atoms forms a ring. In adjacent two carbon atoms
An hydroxyl group (-OH) is attached. Molecular formula is
C5H8(OH)2
Explanation:
