Question

2. When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of the olive oil? (Show all work including the equation you use to solve). (3 points). See page 561 for an example.

Answer 1

Answer:

The answer to your question is C = 1.116 J/g°C

Explanation:

Data

Q = 400 J

mass = 5.6 g

Temperature 1 = T1 = 23°C

Temperature 2 = T2 = 87°C

Specific heat = C = ?

Formula

Q = mC(T2 - T1)

- Solve for C

C = Q / m(T2 - T1)

- Substitution

C = 400 / 5.6 (87 - 23)

- Simplification

C = 400 / 5.6(64)

C = 400 / 358.4

- Result

C = 1.116 J/g°C