Answer:
Product: ethyl L-valinate
Explanation:
If we want to understand what it is the molecule produced we have to an<u>alyze the reagents</u>. We have valine an <u>amino acid</u>, in this kind of compounds we have an <em>amine group</em> (
) and a <em>carboxylic acid</em> group (
). Additionally, we have an <u>alcohol </u>(
) in the presence of HCl (a <u>strong acid</u>) in the first step, and a base (
).
When we have an acid and an alcohol in a vessel we will have an <u>esterification reaction</u>. In other words, an ester is produced. As the <em>first step,</em> the oxygen in the C=O (in the carboxylic acid group) would be protonated. In the <em>second step</em>, the ethanol attacks the carbon in the C=O of the carboxylic acid group producing a new bond between the oxygen in the ethanol and the carbon in the carboxylic acid. In <em>step 3</em>, a proton is transferred to produce a better leaving group (
). In <em>step 4</em>, a water molecule leaves the main structure to produce again the double bond C=O. <em>Finally</em>, a base (
) removes the hydrogen from the C=O bond to produce ethyl L-valinate
See figure 1
I hope it helps!
Answer:
The greatest acceleration when the unbalanced force is applied will be experienced in :
A) The box with a mass of 2 kg
Explanation:
According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.
F = (Final momentum - initial momentum)/time
or
Force is equal to the product of mass and acceleration
F = m x a
Here a= acceleration
m = mass of the object
If Force is constant then acceleration is inversely proportional to mass

A) The box with a mass of 2kg
F = 8 N

a = 4 m/s2
B) The box with the mass of 4kg

a = 2 m/s2
C) The box with a mass of 6kg

a = 1.33 m/s2
D) The box with a mass of 8kg

a = 1 m/s2
The question requires us to draw the structural formula, provide the name and highlight any functional groups for the compound: diethyl ether.
The molecule diethyl ether can be represented as it follows, with two ethyl groups (-CH2CH3) bonded to a oxygen atom:
Note that the functional group ether (R-O-R) is present in the structre and highlighted in blue in the image. The official name of diethyl ether is ethoxyethane.
Adding a catalyst as this would speed up the reaction and the rest would slow it down