All categories

3 years ago

Choose all the answers that apply. Plasma is made of _____.

1 answer:

5 0

'Plasma itself is made up of 91.5% water. It acts as a solvent for important proteins, nutrients, electrolytes, gases, and other substances essential to life.'

Source: https://study.com/academy/lesson/what-is-blood-plasma-function-components.html

Hope this helps! :)

You might be interested in

Why must we do the a lot of quantity urine

serg [7]

Answer:

because

ExplanatioN:

BeCaUsE

7 0

3 years ago

Which scientific discipline belongs in the blue box?

Brums [2.3K]

Answer:

chemistry I think.

Explanation:

I don't need a thanks.

7 0

3 years ago

Read 2 more answers

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

3 years ago

More reactive material can help to stop iron rusting please answer true or false

Tanzania [10]

Answer:

true

Explanation:

and don't look up the link everyone says it's scam bots

8 0

3 years ago

Why is it important to assume that the rate of radioactive decay has remained constant over time?

alexira [117]

It remains constant because it is an element. Just like Chernobyl, there is still active radiation. Radiation is something that stays in the air for a verrrry long time. Radioactivity kill cells, so lets say you have your phone on but its in your pocket.the radiation from the phone is killing your cells.

4 0

3 years ago