All categories

3 years ago

The triangular prisms are similar. Find the volume of the larger prism. Round your answer to the nearest hundredth.

Mathematics

2 answers:

bogdanovich [222]3 years ago

5 0

85.33 in^3 will be your answer, hope this helps!

Ilya [14]3 years ago

4 0

The correct answer is A. 85.33 in^3

You might be interested in

CANNNN SOMEONEEEEE HELPPPP MEEE OUTTTTT !!!!!

USPshnik [31]

Answer:

sin X = 21/ 29

Step-by-step explanation:

Since this is a right triangle

sin X = opp side/ hypotenuse

sin X = 21/ 29

3 0

3 years ago

Read 2 more answers

If f(x) = x2 and g(x) = 3x + 1, then g(f(2))= ?

andreyandreev [35.5K]

Answer:

The value of g[f(2)] = 13

Step-by-step explanation:

Given functions:

f(x) = x²

g(x) = 3x + 1

Find:

The value of g[f(2)]

Computation:

f(x) = x²

By putting x = 2 in f(x)

f(x) = x²

f(2) = 2²

f(2) = 2 × 2

f(2) = 4

So the value of f(2) = 4

Value of f(2) putting in g(x)

g(x) = 3x + 1

g[f(2)] = 3[f(2)] + 1

We know that f(2) = 4

So,

g[f(2)] = 3[f(2)] + 1

g[f(2)] = 3[4] + 1

g[f(2)] = 12 + 1

g[f(2)] = 13

The value of g[f(2)] = 13

8 0

3 years ago

HELP ME PLEASE PLEASE PLEASEEEEE

saw5 [17]

Answer:

B) 14/3 > sq rt 8

Step-by-step explanation:

proof:

14/3=4.67

sq rt 8=2.83

4.67>2.83

5 0

3 years ago

Read 2 more answers

Heeeeeeeelllllllllppppppp plzzzzzzz!!! 0.75g = 2.5

exis [7]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A rectangular box is 10 in. wide, 10 in. tall, and 8 in. long. What is the diameter of the smallest circular opening through w

lutik1710 [3]

Answer:

Diameter of smallest circular opening = 12.81 in

Step-by-step explanation:

Given:-

Width of rectangular box(W)=10 in.

Length of rectangular box(L)=8 in.

Height of rectangular box(H)=10 in.

For box to fit in the smallest circular opening we need to find the diagonal of the rectangular box, therefore

diagonal of rectangular box=diameter of smallest circular opening

So,

$Diagonal\ (d)=\sqrt{width^{2}+length^{2} }$

$d=\sqrt{W^{2} +L^{2} }$

$d=\sqrt{10^{2}+8^{2}}$

$d=\sqrt{100+64}$

$d=\sqrt{164}$

$d=12.81\ in.$

$\therefore\ diagonal\ (d)=12.81\ in$

Therefore diameter of smallest circular opening = 12.81 in.

8 0

4 years ago