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Crank
4 years ago
5

Zinc has a density of 0.258 lb/in³ (pounds per cubic inch).

Mathematics
1 answer:
ollegr [7]4 years ago
5 0

For this case we have that by definition the mass is given by:

m = D * V

Where,

  • <em>D: density </em>
  • <em>V: Volume </em>

The volume of a pyramid is given by:

V = \frac {1} {3} * A * h

Where,

  • <em>A: area of ​​the base </em>
  • <em>h: height </em>

Substituting values ​​we have:

V = \frac {1} {3} * (36) * (2.5)\\V = 30

We now calculate the mass:

m = (0.258) (30)\\m = 7.74\ lb

Answer:

he needs 7.74 pounds of zinc

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A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

6 0
3 years ago
Can someone pleeeeease help me!!
charle [14.2K]

Answer:

I’m pretty sure it’s 73% but I’m not completely sure

6 0
3 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0
3 years ago
Can someone explain what these types of arrows mean please?
Yakvenalex [24]
I think it means grater or less ? Or positive or negative?
8 0
3 years ago
Rearrange your equation to isolate a:(a+b/c)(d-e)=f
sukhopar [10]
To rearrange the equation given, we need to take note the rules in adding, subtracting, multiplying and dividing terms. We rearrange the equation as follows:

<span>((a+b/c)(d-e)=f) 1/(d-e)

</span>(a+b/c = f/(d-e))c

a+b = fc/(d-e)

a = [fc/(d-e)] - b

Hope this answers the question.

8 0
3 years ago
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