Electrochemical cell representation for above reaction is,
Br-/Br2//I2/I-
Reaction at Anode: Br2 + 2e- → 2Br- (1)
Reaction at Cathode: 2I- → I2 + 2e- (2)
Standard reduction potential for Reaction 1 = Ered(anode) = 1.066 v
Standard reduction potential for Reaction 2 = Ered(cathode) = 0.535 v
Eo cell = Ered(cathode) - Ered(anode)
= 0.535 - 1.066
= -0.531v
Now, we know that ΔGo = -nF (Eo cell) ..............(3)
Also, ΔGo = RTln(K) ..........(4)
Equation 3 and 4 we get,
ln (K) = nF (Eo cell) / RT
= 2 X 96500 X (-0.531)/ (8.314 X 298)
∴ K = 1.085 X 10^-18.
Answer:
24.15%
Explanation:
According to the given situation the computation of the percent yield of the reaction is shown below:-
PV = NRT = N =
Mole of =
=
=
= 0.0186
Mole of
= 0.077
Now, the percentage of yield is
=
=
= 24.15%
Therefore for computing the percentage of yield we simply divide the practical yield by theoretical yield and multiply with 100 so that we can get the result into the percentage form.
C=0.10 mol/l
pH=-lg[H⁺]
HCl = H⁺ + Cl⁻
pH=-lgc
pH=-lg0.10=1.0
pH=1.0
I'm not sure but I think it is similar atomic numbers
Answer:
fluorine (F), and chlorine (Cl) because they are both halogens and belong to the same group in the periodic table
Explanation:
The pair of non - metals in the elements given that will have similar properties are chlorine and Fluorine.
This is because they both are elements commonly known by the group name Halogens which belong to group 7A.
Properties of halogens include;
- They are very reactive, have single covalent bonds and readily form other compounds.
- In the gaseous state, they will form diatomic covalent molecules.
Whereas, helium is a group 8 element, oxygen is a group 6 element while carbon is a group 4 element.