Complete Question:
What volume of hydrogen will be produced at STP by the reaction 67.3 g of magnesium with excess water according to the following reaction?
Mg + 2H₂O --> Mg(OH)₂ + H₂
Answer:
62 L
Solution:
Step 1: Calculate Moles of Mg as;
Moles = Mass / M.Mass
Moles = 67.3 g / 24.30 g/mol
Moles = 2.76 moles of Mg
Step 2: <u>Calculate Moles of H₂ as;</u>
According to balance chemical equation,
1 mole of Mg produced = 1 mole of H₂
So,
2.76 moles of Mg will produce = X moles of H₂
Solving for X,
X = 2.76 mol × 1 mol / 1 mol
X = 2.76 mol
Step 3: <u>Calculating volume of H₂,</u>
1 mole of ideal H₂ occupies = 22.4 L Volume at STP
So,
2.76 moles of H₂ will occupy = X L of H₂ at STP
Solving for X,
X = 2.76 mol × 22.4 L / 1 mol
X = 61.82 L ≈ 62 L
Answer:
Climatic condition in coastal regions is milder than the climatic conditions in the continental regions.
Explanation:
Climate in coastal regions is mild. It has both hot summers and winters accompanied by sea breezes. Precipitation and humidity is high in coastal areas. Both the summers and winters have a mild temperature range.
While in continental regions both summer and winters undergo extreme conditions. Summers are extremely hot and winters are extremely cold. They have wide range of climatic exposures such as rainy season, autumn season and spring season in between summer and winter season.
Answer:
Newer
Explanation:
older fossils and rocks are found in lower strata than younger fossils and rock layers because the top layer fossils have not been there as long as the bottom layer fossils to be found deeper in the ground
Answer:
1. kmol of methanol= 3.12 Kmol
2. kmol of water= 5.55 Kmol
3. Liters of methanol= 126.4 L
4. L of water= 100 L
Explanation:
1. kmol of methanol?
32.04 kg methanol ______________ 1 kmol of methanol
100 kg of methanol_______________ X= 3.12 kmol ofmethanol
2. kmol of water?
18.01 kg water ______________ 1 kmol of wáter
100 kg of wáter_______________ X= 5.55 kmol of water
3. Liters of methanol?
0.791 kg methanol _______________________1.00 L of methanol
100kg methanol _______________________x= 126.4 L of methanol
4. L of water?
1kg water _______________________1.00 L of water
100kg water _______________________x= 100 L of water
For a given reaction the half-life, t1/2, of a reactant is the time required for its concentration to reach a value that is the arithmetic mean of its initial and final (equilibrium) value.
Half-life is constant for first-order reactions.
t1⁄2 =
ln 2
k
Half-life is not constant for second-order reactions but rather it varies with initial concentration and k.
t1⁄2 =
1
k·[A]o
half-life → vrijeme poluraspada
For a simple radioactive decay process, half-life, t1/2, is defined as the time required for the activity of a given radioactive isotopes to decrease to half its value by that process.
N = N0 / 2
The half-life is a characteristic property of each radioactive isotope and is independent of its amount or condition.
limiting reactant → mjerodavni reaktant
Limiting reactant is a reactant in a chemical reaction that limits the amount of product that can be formed. The reaction will stop when the entire limiting reagent is consumed. These other reactants are present in excess.
reactant → reaktant
Reactants are initial materials in a chemical reaction.
half-cell → polučlanak
Half-cell is a part of galvanic cell in which oxidations or reduction of an element in contact with water or water solution one of its compounds.
half-wave potential → poluvalni potencijal
Half-wave potential (E1/2) is a potential at which polarographic wave current is equal to one half of diffusion current (id). In a given supporting electrolyte, the half-wave potential is unique for each element and its different valence states and chemical forms. Observation of a current peak at a specific half-wave potential therefore identifies the chemical species producing the current.
