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2 years ago

Answer truthfully:))

Chemistry

1 answer:

BartSMP [9]2 years ago

3 0

Answer:

b) velocity.

c) velocity, m/s²

d)change in velocity, change in direction, change in both velocity and direction.

e) increasing or decreasing

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2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y

Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

Moles Fe -Molar mass: 55.845g/mol-:

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, Fe is limiting reasctant.

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

7 0

2 years ago

HNO3 + KOH + H2O + KNO3 ACID: BASE: SALT:

SSSSS [86.1K]

Explanation:

acid, HNO3

base, KOH

salt ,KNO3

4 0

2 years ago

If 0.580 moles of a monoprotic weak acid (ka = 7.4 10-5 is titrated with naoh, what is the ph of the solution at the half-equiva

Yuri [45]

S is for soil,cl (sometimes c) represents climate,o organisms including humans,r relief,p parent material, or lithology, andt time.

7 0

2 years ago

Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the f

pishuonlain [190]

Answer:

A. The pressure will increase 4 times. P₂ = 4 P₁

B. The pressure will decrease to half its value. P₂ = 0.5 P₁

C. The pressure will decrease to half its value. P₂ = 0.5 P₁

Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

What would happen to the gas pressure inside the cylinder if you do the following?

Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.

V₂ = 0.25 V₁. According to Boyle's law,

P₁ . V₁ = P₂ . V₂

P₁ . V₁ = P₂ . 0.25 V₁

P₁ = P₂ . 0.25

P₂ = 4 P₁

Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.

T₂ = 0.5 T₁. According to Gay-Lussac's law,

$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}$

Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

$P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}$

P₂ in terms of the ideal gas equation is:

$P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}$

3 0

3 years ago

Determine the mass of each sample 1.55 kmol sulfur trioxide

xxMikexx [17]

Explanation:

Given parameters:

Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole

Unknown:

Mass of the sulfur trioxide = ?

Solution:

To solve for the mass of the sample of sulfur trioxide:

Find the molar mass of the compound i.e SO₃

atomic mass of S = 32g

O = 16g

molar mass = 32 + 3(16) = 80g/mol

Use the formula below:

mass of SO₃ = number of moles x molar mass

mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg

Learn more:

mole calculation brainly.com/question/13064292

#learnwithBrainly

3 0

2 years ago

Answer truthfully:))​

Answer truthfully:))