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3 years ago

Answer truthfully:))

Chemistry

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

b) velocity.

c) velocity, m/s²

d)change in velocity, change in direction, change in both velocity and direction.

e) increasing or decreasing

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Mars2501 [29]

Answer:

Explanation: Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons.........

5 0

2 years ago

Consider the solubilities of a particular solute at two different temperatures. Temperature ( ∘ C ) Solubility ( g / 100 g H 2 O

grin007 [14]

Answer:

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water = $\frac{32.2}{100}g=0.322 g$

Mass of solute in soluble in 56.0 grams of water:

$0.322\times 56.0=18.032 g$

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water = $\frac{70.2}{100}g=0.702 g$

Mass of solute in soluble in 56.0 grams of water:

$0.702 \times 56.0=39.312 g$

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.

8 0

3 years ago

What is emitted when an electron returns to its lower energy level?

Yakvenalex [24]

Answer:

When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level. The energy of the photon is the exact energy that is lost by the electron moving to its lower energy level.

Explanation:

4 0

3 years ago

Read 2 more answers

1. How many cm are equal to 1.45 m?

geniusboy [140]

Explanation:

(1) 1 m = 100 cm

1.45 m = 100 × 1.45 cm = 145 cm

(2) 1 kg = 1000 g

325 g = 0.325 kg

(3) 1 L = 1000 mL

0.0024 L= 2.4 mL

(4) 1 km = 1000 m

$1.55\times 10^4\ m=1.55\times 10^4\times 0.001=15.5\ km$

(5) 1 mm = 0.001 m

$4.75\times 10^{-2}\ m=4.75\times 10^{-2}\times 1000\ mm\\\\=47.5\ mm$

(6) 1 kg = 100000 cg

0.459 kg = 45900 cg

(7) 1 dm = 10⁻⁴ dm

5,995 dm = 5,995 × 10⁻⁴ km

(8) 1 g = 1000 mg

450 g = 450000 mg

(9) 1 dm = 100 m

0.003 dm = 0.3 mm

(10) 1 mL = 0.001 l

4.567 × 10⁴ mL = 45.67 L

8 0

3 years ago

N2 (g) + 3 H2 (g) → 2 NH3 (g)

shusha [124]

This problem is asking for the rate of disappearance of gaseous nitrogen, given the rate of appearance of ammonia and the chemical reaction. At the end, the result turns out to be -0.228 M/s.

<h3>Rates of appearance and disappearance</h3>

In chemical kinetics, one of the most relevant calculations are based on rates of appearance and disappearance of chemical species in a chemical reaction. This can be calculated via rate portions based on the stoichiometric coefficients in the reaction.

Thus, for this problem, one can write:

$\frac{r_{N_2}}{-1} =\frac{r_{H_2}}{-3} =\frac{r_{NH_3}}{2}$

Where the rate of appearance or disappearance is divided by the stoichiometric coefficient. Therefore, one can solve for the rate of disappearance of N2 with:

$\frac{r_{N_2}}{-1} =\frac{r_{NH_3}}{2}\\\\r_{N_2}=\frac{r_{NH_3}*-1}{2}\\\\r_{N_2}=\frac{0.456M/s*-1}{2}\\\\r_{N_2}=-0.228M/s$

Learn more about chemical kinetics: brainly.com/question/26351746

3 0

2 years ago

Answer truthfully:))​

Answer truthfully:))