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gladu [14]
3 years ago
5

12.5 mL of 0.280 M HNO3 and 5.0 mL of 0.920 M KOH are mixed. Is the resulting solution acidic, basic or neutral?

Chemistry
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

The resulting solution is basic.

Explanation:

The reaction that takes place is:

  • HNO₃ + KOH → KNO₃ + H₂O

First we <u>calculate the added moles of HNO₃ and KOH</u>:

  • HNO₃ ⇒ 12.5 mL * 0.280 M = 3.5 mmol HNO₃
  • KOH ⇒ 5.0 mL * 0.920 M = 4.6 mmol KOH

As <em>there are more KOH moles than HNO₃,</em> the resulting solution is basic.

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A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I
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Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

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with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

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Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

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final temperature water T2 = 21.3 °C

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msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

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Answer:

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