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4 years ago

Air leaves a tire when the tire valve is opened because

1 answer:

3 0

Air leaves a tire when the tire valve is opened because "the pressure outside the tire is lower than the pressure inside the tire".

<u>Answer:</u> Option A

<u>Explanation:</u>

When air is filled in tires it get into more compact area than outer atmosphere, therefore particles in the tire are very close to each other and exert pressure continuously on tire walls to get out of it. Thus the material of tire need to be pressure resistant as much possible, here quality of tires lie actually.

After opening the tire valve, air start leaving with huge sound as the strain outside the tire is weaker than that inside the tire. The molecules strike with the same force on a larger area and pressure starts diminishing.

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Which of these factors influences air temperature?

Ksju [112]

Answer:

Explanation:

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3 years ago

Answer each of the following questions with increases, decreases, or does not change.

Kaylis [27]

Answer:

1) Increases

2) decreases

3) increases

4) decreases

Explanation:

When the intermolecular forces in a liquid increases, the greater vapour pressure of the liquid decreases accordingly.

Since the vapour pressure is proportional to temperature, as temperature increases, the vapour pressure increases alongside.

As intermolecular forces increases, the boiling point increases accordingly since more energy is required to break intermolecular bonds.

Lastly, the greater the surface area, tell greater the vapour pressure since more liquid surface area is now available.

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4 years ago

The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?

siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = $K_a=1.9\times 10^{-5}$

The equilibrium reaction for dissociation of $HN_3$ (weak acid) is,

$HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

Dissociation constant is given as:

$K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

$1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}$

By solving the terms, we get value of $(\alpha)}$

$\alpha=0.00686832$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.002747)$

$pH=2.56$

Therefore, the pH of the solution is, 2.56.

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4 years ago

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Answer:

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3 years ago

UNO [17]

Nucleus

Because that’s where all the chemical cell activity decisions take place

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3 years ago