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Svetach [21]
3 years ago
12

What types of star can explode in a supernova

Chemistry
1 answer:
horrorfan [7]3 years ago
4 0
For a star to explode as a Type II supernova, it must be at several times more massive than the sun<span> (estimates run from eight to 15 solar masses). Like </span>the sun<span>, it will eventually run out of hydrogen and then helium fuel at its core. However, it will have enough mass and pressure to fuse carbon.
i had to right an essay on this stuff.</span>
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Help me please!!!!!!!!!!!!!
Mariana [72]

Answer:

D.

Explanation:

Hope this helps

4 0
3 years ago
The main interactions between molecules of hydrogen chloride are examples of
saveliy_v [14]
Answer:
            <span>The main interactions between molecules of hydrogen chloride are examples of Dipole-Dipole Interactions.

Explanation:
                   The bond between Hydrogen and Chlorine is Polar Covalent Bond as the electronegativity difference between these two elements is 0.96 which is greater than 0.4. Chlorine being more electronegative attracts the electrons from Hydrogen making the Hydrogen partial positive and itself partial negative. The two poles on HCl makes it a dipole. Now, one HCl (a dipole) interacts with another HCl (another Dipole) through their opposite charges and creates Dipole-Dipole Interaction. The picture is as below, the green dashed lines are interactions,

</span>

6 0
3 years ago
A sample of neon occupies a volume of 752 ml at 25 0
lyudmila [28]
V_{initial} = 752\:mL
T_{initial} = 25.0^0C
converting to Kelvin
TK = TC + 273
TK = 25.0 + 273 → TK = 298.0 → T_{initial} = 298.0\:K
V_{final} = ? (in\:milliliters)
T_{final} = 50.0^0C
TK = TC + 273
TK = 50.0 + 273 → TK = 323.0 → T_{final} = 323.0\:K

By the first Law of Charles and Gay-Lussac, we have: 
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }

Solving:
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }
\frac{ 752 }{ 298.0 } = \frac{ V_{f} }{ 323.0 }
Product of extremes equals product of means:
298.0* V_{f} = 752*323.0
298.0 V_{f} = 242896
V_{f} = \frac{242896}{298.0}
\boxed{\boxed{V_{f} \approx 815.08\:mL}}\end{array}}\qquad\quad\checkmark
5 0
4 years ago
Different between intermolecular and intra molecular dehydration​
harkovskaia [24]

Answer: Intermolecular bonds are the forces between the molecules. Intramolecular are the forces within two atoms in a molecule.

Explanation:

4 0
3 years ago
An object with a pre-weighed mass of exactly (and correctly) 0.54 g is given to 2 students. One student obtains a weight of 0.59
Alina [70]

Answer:

Both student have same percent error.

Explanation:

Given data:

Actual mass of object = 0.54 g

Measured value by one student = 0.59 g

Measured value by second student = 0.49 g

Percent error = ?

Solution:

Formula

Percent error = (measured value - actual value / actual value) × 100

Percent error of first student:

percent error = (0.59 g - 0.54 / 0.54 ) ×100

percent error =  9.3 %

Percent error of second student:

Percent error = (0.49 g - 0.54 / 0.54 ) ×100

Percent error = - 9.3 %

Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.

3 0
4 years ago
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