Answer:
Density of the substance is 0.7
Explanation:
4.2/6 = 0.7
atomic number is equal to proton number
so the proton number will be 87
Answer:
1.99 x 10⁻¹⁸J
Explanation:
Given parameters:
Frequency of the wave = 3 x 10¹⁵Hz
Unknown:
Energy of the photon = ?
Solution:
To solve this problem, we use the expression below;
E = hf
Where E is the energy, h is the Planck's constant and f is the frequency
Now insert the parameters and solve for E;
E = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J
Answer:
Explanation:
H2SO4 let S be x
2(1) + x + 4(-2) = 0
2 + x - 8 = 0
x - 6 = 0
x = 6
For H2S7O8 let S be x
2(1) + 7(x) + 8(-2) = 0
2 + 7x - 16 = 0
7x - 14 = 0
7x = 14
x = 14/7
x = 2
:- H2SO4 as the larger percentage
