Higher Resolution i guess it depends on what it’s requiring
Answer:
please find the attachment of the flowchart.
Explanation:
In this question, a start block is used to start the program, in the parallelogram box we input the value from the user end and in the diamond box, we check the input is not equal to 0. In the next diamond box, it checks the given input value and print value, and at the last, we stop the code.
Please find the program and its output in the attached file.
Answer:
The solution code is written in Python 3.
- import random
-
- count = 0
- flag = False
- guess = int(input("Input your guess (2-12): "))
-
- while(count <=3):
- dice1 = random.randint(1, 7)
- dice2 = random.randint(1, 7)
-
- if((dice1 + dice2) == guess):
- flag = True
-
- count += 1
-
-
- if(flag):
- print("User wins!")
- else:
- print("Computer wins!")
Explanation:
A Random generator is needed for this question and therefore we start by importing Python random class (Line 1)
Next, create one counter variable,<em> count</em>, to ensure there will be only three rolling of the dices (Line 3). We need another variable, <em>flag</em>, to track the status if the two dices equal to the <em>guess</em> number chosen by user (Line 4).
Next, prompt use to input a guess number (Line 5).
Within the while loop, we can use random class method <em>randint() to </em>generate random integer. The arguments 1 and 7 will give one random number ranged from 1 to 6 for <em>dice1</em> and<em> dice2</em>, respectively (Line 8 - 9).
If the total of<em> dice1 + dice2</em> equal to user <em>guess</em>, we turn the<em> flag </em>to <em>True</em>. If not, the <em>flag </em>will remain <em>False</em> after completing entire while loop.
If the <em>flag </em>turned to <em>True</em>, print the message "User Wins!" else print the message ("Computer wins!")
Answer: option A) First
In a circular linked list the last node points to the first node.
Explanation: As in a circular linked list, the node will point to its next node. Since the node next to last node is the first node hence last node will point to first node in a circular way. The elements points to each other in a circular path which forms a circular chain.
