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SIZIF [17.4K]
3 years ago
11

Which of the following is not a skill set required by data scientists? A. Programming expertise B. Big data expertise C. Telecom

munications expertise D. Database systems expertise
Computers and Technology
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

Explanation:Option C is the correct answer.

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A 30V battery maintains a current through a 10 Ω Resistor. What is the current flow through the resistor?
Troyanec [42]

Answer:

3 amps

Explanation:

because as per ohm's law. "electric current is proportional to voltage and inversely proportional to resistance"

7 0
3 years ago
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
2 years ago
Select the phrases that apply to Java classes or methods.
oee [108]

Answer:

graficar una lista de entradas

graficar una lista de entradas

crear un nuevo objeto

condiciones de prueba

romper un ciclo

romper un ciclo

Explanation:

7 0
2 years ago
Is windows 7 professional faster than home premium?
Olin [163]
Widows 7 is no longer supported for anti virus, I recommend a windows 10 license
8 0
2 years ago
What are 6 external parts or perpherals of a computer system and identify output from input devices.
n200080 [17]
40. External Peripherals of a Computer systems are the following: -> Keyboard – this is an input device -> Mouse – This is an input device also -> Printer – this is an output device -> Flashdrive – This is a storage device -> Monitor – this is an output device -> external hard drive – this is a storage device Output device are those devices that communicate the results of the data processing to the user Input device are those device that communicate the results of the data processing to the computer system Storage device are those device that stores data.
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3 years ago
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