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mestny [16]
4 years ago
14

a is a circuit that is energized but dose not allow useful current to flow on the circuit because of a break in the current path

Physics
1 answer:
strojnjashka [21]4 years ago
3 0
A "open circuit" is one that doesn't permit current to flow because of a break in the path.
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What is the momentum of a 50 kg object traveling 200 m/s
garik1379 [7]
Momentums equation is just p=mv
mass times velocity so 50x200
p=10,000
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3 years ago
How do you convert mass to weight and visa versa
Darina [25.2K]
To change from mass to weight is Fw = 30 kg * 9.8 m/s^2 = 294 N. To change from weight to mass divide by gravity (9.8 m/s^2).
6 0
3 years ago
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Imagine a negative test charge sitting at the coordinate origin (0,0). Two bunches of positive charges are located on the x-axis
Oxana [17]

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

5 0
3 years ago
Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid
Korolek [52]

Answer:

a

    z= 2.5 \ m

b

   z =  (1 \ m ,  4 \ m )

Explanation:

From the question we are told that

     Their distance apart is  d =  5.00 \ m

      The  wavelength of each source wave \lambda =  6.0 \ m

Let the distance from source A  where the construct interference occurred be z

Generally the path difference for constructive interference is

              z - (d-z) =  m \lambda

Now given that we are considering just the straight line (i.e  points along the line connecting the two sources ) then the order of the maxima m =  0

  so

        z - (5-z) =  0

=>     2 z - 5 =  0

=>     z= 2.5 \ m

Generally the path difference for destructive  interference is

           |z-(d-z)| = (2m + 1)\frac{\lambda}{2}

=>         |2z - d |= (0 + 1)\frac{\lambda}{2}

=>        |2z - d| =\frac{\lambda}{2}

substituting values

          |2z - 5| =\frac{6}{2}

=>      z  =  \frac{5 \pm 3}{2}

So  

      z =  \frac{5 + 3}{2}

      z =  4\ m

and

      z =  \frac{ 5 -3 }{2}

=>   z =  1 \ m

=>    z =  (1 \ m ,  4 \ m )

7 0
3 years ago
Please answer someone!!
Naily [24]

Answer:

10m

Explanation:

3 0
3 years ago
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