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Strike441 [17]
3 years ago
14

31231802938102938x1923193819023

Mathematics
2 answers:
Komok [63]3 years ago
5 0

Answer:

6.006481e+28

Step-by-step explanation:

hope it helped

MA_775_DIABLO [31]3 years ago
4 0
<h2>Answer:</h2><h2>Your final answer is 6.006481e+28</h2><h2>Step-by-step explanation:</h2><h2></h2><h2>You just multiply.</h2><h2></h2><h2>Hope this helps, have a great day, stay safe, and positive.</h2><h2></h2><h2>:)</h2>
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Solve the quadratic equation by completing the square. x2 + 6x + 7 = 0
ruslelena [56]
Hello,

x²+2*3x+3²+7-9=0
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3 years ago
X=y+1400<br> 0.08x+0.05=840
mezya [45]

Answer:

x = 7000

y = 5600

(7000, 5600)

Step-by-step explanation:

To solve the system of equations means to find the point of intersection (graphically). You are finding what value of 'x' and what value of 'y' fits both equations.

x = y + 1400

0.08x + 0.05y = 840

We can solve using the method <u>substitution</u>, where you replace a variable in one equation with an equivalent expression.

<u>Since "x" is y + 1400, we can replace "x" in the second equation.</u>

0.08x + 0.05y = 840

0.08(y + 1400) + 0.05y = 840    

Distribute over brackets by multiplying 0.08 with y, then 0.08 with 1400.

0.08y + 112 + 0.05y = 840         Collect like terms (with "y" variable)

112 + 0.13y = 840

Now isolate "y" in the simplified equation.

112 - 112 + 0.13y = 840 - 112         Subtract 112 from both sides

0.13y = 728

0.13y/0.13 = 728/0.13         Divide both sides by 0.13

y = 5600         Solved for y

We can substitute "y" with 5600 in any other equation that has "x".

x = y + 1400

x = 5600 + 1400          Add

x = 7000         Solved for x

You may express the answer as a coordinate, or an ordered pair (x, y).

The solution is (7000, 5600).

3 0
3 years ago
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B/ 21 Marks
Serggg [28]

Answer:

y = 3x + 1.

Step-by-step explanation:

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= 10/1/ 3-0

= 9/3

= 3.

Using the point-slope form for a straight line:

y-y1 = m(x-x1)     (m = slope)

y - 10 = 3(x - 3)

y - 10 = 3x - 9

y = 3x - 9 + 10

y = 3x + 1  is the required equation.

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3 years ago
Two positive integers have a product of 200.
sattari [20]

Since 200 is a constant, of x, move 200 out of the integral. 200x+c. Constant is a fixed value that does not change.

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