Answer:Following is the c++ code for the problem:
#include <iostream>
using namespace std;
int main() {
int number;
cout<<"Enter the number"<<endl;
cin>>number;
int i=0,c=0,odd[500];
while(i<=number)//loop for printing the numbers form 0 to number.
{
cout<<i<<" ";
if(i%2!=0)// storing in the odd array if the number is odd.
{
odd[c++]=i;//storing odd numbers..
}
i++;
}
cout<<endl;
i=0;
cout<<"The odd numbers are "<<endl;
while(i<c)//loop to print the odd numbers.
{
cout<<odd[i]<<" ";
i++;
}
cout<<endl<<"The prime numbers are "<<endl;
i=0;
int sum=0;
while(i<c)//loop to print the prime numbers..
{
int div=2;
while(div<odd[i])
{
if(odd[i]%div==0)
break;
div++;
}
if(div==odd[i])
{
cout<<odd[i]<<" ";
sum+=odd[i];//updating the sum..
}
i++;
}
cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..
return 0;
}
Output :
Enter the number
49
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
The odd numbers are
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
The prime numbers are
3 5 7 11 13 17 19 23 29 31 37 41 43 47
The sum of odd prime numbers is 326
.
Explanation:
First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.
