Ask question

Ask question

All categories

2 years ago

9

In shop class, you make a table. The sides of the table measure 36" and 18". If the diagonal of the table measures 43", is the t

able “square"?

1 answer:

Lunna [17]2 years ago

5 0

Answer: 75

Step-by-step explanation: took test and got it right. this is not fake like other people

You might be interested in

Sarah invested £12000 in a unit trust 5 years ago, the value of the unit trust increased by 7% per annum for each of the last 3

trasher [3.6K]

Answer:

The current price of the unit trust = £13,831.72

Step-by-step explanation:

Since it increased 7% per annum in last three years and decreased by 3% per annum before that, it implies that the unit trust decreased by 3% per annum for the first 2 years and then increased by 7% per annum for the next 3 years in the total 5 year period

The invested after 2 years = 12,000*(1-0.03)^2 = £11,290.8

This amount then grows by 7% for the next 3 years making it = 11,290.80*(1+0.07)^3 = £13,831.7155 = £13,831.72 (Rounded to 2 decimals)

The current price of the unit trust = £13,831.72 (Rounded to 2 decimals)

6 0

3 years ago

Help please! Ty! Ratios

Kamila [148]

Answer:

Ratios to roses to lilies....6:9

Reduced.....2:3

Step-by-step explanation:

Pretty simple doesn't need explaining

8 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

Could anybody please help me on this one? I'm really stuck on this.

san4es73 [151]

( c^2 )^3 = 64 <=>( c^2 )^3 = 4^3 <=> c^2 = 4 <=> c = 2 or c = -2.

7 0

3 years ago

The sum of two numbers is 33.the larger number is 3 more than two times the smaller number.what are the numbers?

e-lub [12.9K]

Answer: The numbers are 10 and 23

Step-by-step explanation:

Let the smaller number be x

And the larger number be y

Ist sentence;

1. The sum of two numbers is 33.

X + y= 33 .........eqn 1

2. second sentence

the larger number is 3 more than two times the smaller number.

Y = 3 +2x

Put y into eqn 1

X+ 3 +2x = 33

3x= 33- 3

3x= 30

X = 30/3

X= 10 and y= 3+ 2x

Y= 3+ 2(10)

Y = 3+ 20

Y= 23

Therefore the two numbers are 10 and 23

8 0

3 years ago