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3 years ago

How to find the circumference of a circle with a rectangle inside and a perpendicular line?

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Use the Pythagorean Theorem to find the diagonal of the rectangle.

The diagonal of the rectangle is the diameter of the circle.

Diameter (d) = 2 · radius (r)

Circumference (C) = 2· π · r → π · d

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If 3x + 6 = 18, then x = ?

zaharov [31]

Answer:

X=4

Step-by-step explanation:

$3x + 6 = 18 \\ 3x = 18 - 6 \\ 3x = 12 \\ x = 4$

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3 years ago

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Step-by-step explanation:

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3 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

Step-by-step explanation:

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$