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3 years ago

F(x) = 6x-2 and g(x) = 2x+4 (f-g)(x)

Mathematics

2 answers:

Effectus [21]3 years ago

5 0

f(x) = 6x-2 and g(x) = 2x+4 (f-g)(x)

= 6x - 2 - 2x +4

Subtract like terms:

4x -6

Vanyuwa [196]3 years ago

4 0

Answer:

4x-6

Step-by-step explanation:

(f-g)(x)= (6x-2)-(2x+4)

6x-2-2x-4

6x-2x-2-4

4x-6

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Find 'x' in the following

Juli2301 [7.4K]

Answer:

x = 130

Step-by-step explanation:

Sum of all the angle of quadrilateral = 360°

50 + 45 + 35 + ∠ADC = 360

130 + ∠ADC = 360

∠ADC = 360 - 130

∠ADC = 230

x = Reflex ∠ADC

= 360 - 230

= 130

6 0

3 years ago

Read 2 more answers

When creating a histogram, the first recorded scale is 0 to 10. What should the second scale indicate?

klio [65]

Answer:

A) 10-20

Step-by-step explanation:

Its A because it started with 0 and it went to 10 so it adds 10 each time cause it gave us the hint with 0 to 10,

I hope this helps

6 0

2 years ago

Simplify the expression

finlep [7]

Answer:

$\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}$

Step-by-step explanation:

We have the expression:

$\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x}$

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

$(\frac{2}{2} )\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x}$

Now we can directly add the terms to get:

$\frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x} = \frac{x - 6}{4*x}$

We can't simplify this anymore

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3 years ago

What is the d value in the following arithmetic sequence? -7, -2, 3, 8, …

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

You add five to -7 you get -2 add five to -2 you get 3 and so on.

4 0

3 years ago

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The following question involves a standard deck of 52 playing cards. In such a deck of cards there are four suits of 13 cards ea

olasank [31]

Answer:

(a)No. The probability of drawing a specific second card depends on the identity of the first card.

(b)4/663

(d) 8/663

Step-by-step explanation:

(a)The events are not independent because we are drawing cards without replacement and the probability of drawing a specific second card depends on the identity of the first card.

(b) P(ace on 1st card and jack on 2nd).

$P$(Ace on 1st card) =\dfrac{4}{52}\\ P$(Jack on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(ace on 1st card and jack on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(c)P(jack on 1st card and ace on 2nd)

$P$(Jack on 1st card) =\dfrac{4}{52}\\ P$(Ace on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(jack on 1st card and ace on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(d)Probability of drawing an ace and a jack in either order.

We can either draw an ace first, jack second or jack first, ace second.

Therefore:

P(drawing an ace and a jack in either order) =P(AJ)+(JA)

From parts (b) and (c) above:

$P$(jack on 1st card and ace on 2nd) =\dfrac{4}{663}\\P$(ace on 1st card and jack on 2nd) =\dfrac{4}{663}\\$Therefore:\\P(drawing an ace and a jack in either order)=\dfrac{4}{663}+\dfrac{4}{663}\\=\dfrac{8}{663}$

6 0

3 years ago