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kykrilka [37]
3 years ago
10

Describe the cross section The cross section is ain) (select)

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

A cross section is the shape we get when cutting straight through an object. The cross section of this object is a triangle. It is like a view into the inside of something made by cutting through it. This is a cross-section of a piece of celery.

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Mark got 19 presents for his birthday.His friend got 11.How many more did Mark receive?
lara [203]
Mark received 8 more.
4 0
4 years ago
Read 2 more answers
Lucy has $60,000 in a savings account that earns simple interest of 14% per year. How much will she have in her account after 5
choli [55]

Answer:

$42,000

Step-by-step explanation:

60,000 × .14 × 5 = 42,000

4 0
3 years ago
How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
C(x)=4x-2 and d(x)=x^(2)+5, what is (c*d)(x)
lawyer [7]

Answer:4x^3-2x^2+20x-10

Step-by-step explanation:

5 0
3 years ago
What is the explicit rule for the following sequence: 10, 13, 16, 19, …?
Svetradugi [14.3K]

Answer:

Option B. f(n) = 10 + (n-1)(3)

Step-by-step explanation:

In order to know the correct answer, you need to put some values of n into the equation given.

Let's begin with a value of n = 1. Now, let's discard some options.

If n = 1, means that the bracket (n-1) always become zero (cause 1-1 = 0), this means that no matter what number you multiply or divide, the result will always be zero.

Option C and D can be easily discarted because when you put n = 1, you get the following:

-10 + (1-1)(3) = -10 + (0)(3) = -10 + 0 = -10.

In option D, would be the same, only that instead of using 3, you'll use -3 but -3 * 0 = 0. The final result is -10, and the sequence begins in 10 positive. That's why Option C and D cannot be the correct option.

We have now option A and B, the difference is on the signus of the 3 (option A is negative and option B is positive). Again, let's use logic, both options, when n = 1, will give the same result, 10. However if we use another number different than 1, ex 2, the result would be different in both options:

n = 2.

a) f(2) = 10 + (2-1)(-3) = 10 + (1)(-3) = 10 - 3 = 7.

As you can see in option A, the next number is decreased, it's not 13.

Therefore, the only and correct option would be the b, and here's the proof:

f(1) = 10 + (1-1)(3) = 10 + 0 = 10

f(2) = 10 + (2-1)(3) = 10 + 3 = 13

f(3) = 10 + (3-1)(3) = 10 + 6 = 16

f(4) = 10 + (4-1)(3) = 10 + 9 = 19

5 0
3 years ago
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