V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
Answer:
I think the answer is 60 or 70 or 65
Cross multiply:-
3(b - 2) = (2b - 5)(b + 2)
3b - 6 = 2b^2 + 4b - 5b - 10
2b^2 - 4b - 4 = 0
b^2 - 2b - 2 = 0
b = 2.73, -0.73 Answer
1) 12 * 9 = 108 cm² - part 1
2) 12 - 3 - 3 = 6 cm
3) 6 * 4 = 24 cm² - part 2
4) 108 + 24 =
132 cm ² - the area.