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telo118 [61]
3 years ago
15

Angle θ is in standard position. If tan ⁡ θ < 0 and cos ⁡ θ = − 4/5 , find sin ⁡ θ .

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

The value found is.

sin θ = 0.6

Step-by-step explanation:

We know that the value of cosθ is given -4/5

cosθ = -4/5

First, lets finds the angle θ by taking inverse of cosine of -4/5

θ = cos⁻¹ (-4/5)

θ = 143.13°

Substitute the found θ = 143.13° it in tanθ to see if satisfies the equation tanθ < 0:

tanθ < 0

tan(143.13°) < 0

-0.75 < 0

Hence the equation is satisfied.

Which means that θ is equals to 143.13° and can be used to find sinθ

sinθ = sin 143.13°

sin 143.13° = 0.6

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arsen [322]
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3 years ago
A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t
sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is  11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

\text{Area of painting}=l\times b

\text{Area of painting}=24\times 11

\text{Area of painting}=264 \text{ in}^2

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

\text{Area of painting with mat}=30\times 17

\text{Area of painting with mat}=510 \text{ in}^2

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\

\text{Area of mat}=510-264

\text{Area of mat}=246 \text{ in}^2

Hence, the area of the mat is 246 in².

6 0
2 years ago
Can a pair of lines be both parallel and skew?
adelina 88 [10]
No: Skew lines<span> are defined as two </span>lines<span> that do not intersect and are not parallel.</span>
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3 years ago
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Mnenie [13.5K]

Answer: 2 or 3

Step-by-step explanation:

Which ever line is going through the most points

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Breadth
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Answer:

Volume of a cuboid = (length × breadth × height) cubic units.

= (l × b × h) cubic units.

(Since area = ℓ × b)

Volume of a cuboid = area of one surface × height cubic units

Let us look at the given cuboid.

The length of the cuboid = 5 cm

The breadth of the cuboid = 3 cm

The height of cuboid (thickness) = 2 cm

The number of 1 cm cubes in the given cuboid = 30 cubes = 5 × 3 × 2

We find that volume of the given cuboid with length 5 cm, breadth 3 cm and height 2 cm is 30 cu cm.

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